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An impulse is applied to a moving object with a force at an angle of 120^0 with velocity vector. The angle between the impulse vector and the change I'm the momentum vector is?
Most Upvoted Answer
An impulse is applied to a moving object with a force at an angle of 1...
An impulse is defined as the change in momentum of an object, and it is a vector quantity. When an impulse is applied to a moving object, it can cause a change in both the magnitude and direction of the object's momentum. In this case, the force is applied at an angle of 120 degrees with the velocity vector of the object.

To determine the angle between the impulse vector and the change in momentum vector, we need to analyze the components of the vectors involved.

Let's break down the problem step by step:

1. Decompose the velocity vector:
First, we need to decompose the velocity vector into its horizontal and vertical components. Let's assume the velocity vector is V and its components are Vx and Vy.

2. Calculate the impulse vector:
The impulse vector is given by the product of the force and the time interval over which it is applied. Let's assume the impulse vector is I and its components are Ix and Iy.

3. Calculate the change in momentum vector:
The change in momentum vector is given by the product of the mass and the change in velocity. Let's assume the change in momentum vector is Δp and its components are Δpx and Δpy.

4. Calculate the angle between the impulse vector and the change in momentum vector:
Now, we can use the dot product formula to find the angle between two vectors. The dot product of two vectors A and B is given by the equation A · B = |A| |B| cosθ, where θ is the angle between the two vectors.

In our case, the dot product of the impulse vector I and the change in momentum vector Δp is I · Δp = Ix Δpx + Iy Δpy. The magnitude of the impulse vector is |I| = √(Ix^2 + Iy^2), and the magnitude of the change in momentum vector is |Δp| = √(Δpx^2 + Δpy^2).

By substituting these values into the dot product equation, we get:

Ix Δpx + Iy Δpy = √(Ix^2 + Iy^2) √(Δpx^2 + Δpy^2) cosθ

Now, we can solve this equation to find the angle θ.

By solving the equation, we can find the angle between the impulse vector and the change in momentum vector. The angle will depend on the magnitudes of the impulse vector and the change in momentum vector, as well as the components of each vector.
Community Answer
An impulse is applied to a moving object with a force at an angle of 1...
Angle is equal to 60 degree I guess
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An impulse is applied to a moving object with a force at an angle of 120^0 with velocity vector. The angle between the impulse vector and the change I'm the momentum vector is?
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An impulse is applied to a moving object with a force at an angle of 120^0 with velocity vector. The angle between the impulse vector and the change I'm the momentum vector is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An impulse is applied to a moving object with a force at an angle of 120^0 with velocity vector. The angle between the impulse vector and the change I'm the momentum vector is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An impulse is applied to a moving object with a force at an angle of 120^0 with velocity vector. The angle between the impulse vector and the change I'm the momentum vector is?.
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