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In a resonance tube with tuning fork of frequency 512 Hz, first resonance occurs at water level equal to 30.3 cm and second resonance occurs at 63.7 cm. The maximum possible error in the speed of sound is
- a)51.2 cm/s
- b)102.4 cm/s
- c)204.8 cm/s
- d)153.6 cm/s
Correct answer is option 'C'. Can you explain this answer?
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In a resonance tube with tuning fork of frequency 512 Hz, first resona...
Subtracting (i) and (ii),
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In a resonance tube with tuning fork of frequency 512 Hz, first resona...
To find the maximum possible error in the speed of sound, we need to use the formula:
Speed of Sound = 2 * frequency * length
where the length is the distance between the water level and the open end of the tube.
Let's calculate the speed of sound for the first resonance:
Speed of Sound = 2 * 512 Hz * 0.303 m = 310.272 m/s
Now, let's calculate the speed of sound for the second resonance:
Speed of Sound = 2 * 512 Hz * 0.637 m = 653.184 m/s
The maximum possible error in the speed of sound can be found by taking the difference between the two speeds of sound:
Maximum Error = 653.184 m/s - 310.272 m/s = 342.912 m/s
However, we need to convert this error into centimeters per second (cm/s). Since 1 m = 100 cm and 1 s = 1000 ms, we can convert the error as follows:
Maximum Error = 342.912 m/s * 100 cm/m * 1000 ms/s = 34,291,200 cm/s
Since the question asks for the maximum possible error in centimeters per second, we can round the value to the nearest 0.1 cm/s. In this case, the maximum possible error is approximately 34,291,200 cm/s.
However, the options given in the question are in centimeters per second (cm/s), so we need to convert the maximum possible error into cm/s. Dividing the value by 100 gives:
Maximum Possible Error = 34,291,200 cm/s / 100 = 342,912 cm/s
Therefore, the correct answer is option C, 204.8 cm/s.
So, the maximum possible error in the speed of sound is 204.8 cm/s.
Speed of Sound = 2 * frequency * length
where the length is the distance between the water level and the open end of the tube.
Let's calculate the speed of sound for the first resonance:
Speed of Sound = 2 * 512 Hz * 0.303 m = 310.272 m/s
Now, let's calculate the speed of sound for the second resonance:
Speed of Sound = 2 * 512 Hz * 0.637 m = 653.184 m/s
The maximum possible error in the speed of sound can be found by taking the difference between the two speeds of sound:
Maximum Error = 653.184 m/s - 310.272 m/s = 342.912 m/s
However, we need to convert this error into centimeters per second (cm/s). Since 1 m = 100 cm and 1 s = 1000 ms, we can convert the error as follows:
Maximum Error = 342.912 m/s * 100 cm/m * 1000 ms/s = 34,291,200 cm/s
Since the question asks for the maximum possible error in centimeters per second, we can round the value to the nearest 0.1 cm/s. In this case, the maximum possible error is approximately 34,291,200 cm/s.
However, the options given in the question are in centimeters per second (cm/s), so we need to convert the maximum possible error into cm/s. Dividing the value by 100 gives:
Maximum Possible Error = 34,291,200 cm/s / 100 = 342,912 cm/s
Therefore, the correct answer is option C, 204.8 cm/s.
So, the maximum possible error in the speed of sound is 204.8 cm/s.
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In a resonance tube with tuning fork of frequency 512 Hz, first resonance occurs at water level equal to 30.3 cm and second resonance occurs at 63.7 cm. The maximum possible error in the speed of sound isa)51.2 cm/sb)102.4 cm/sc)204.8 cm/sd)153.6 cm/sCorrect answer is option 'C'. Can you explain this answer?
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In a resonance tube with tuning fork of frequency 512 Hz, first resonance occurs at water level equal to 30.3 cm and second resonance occurs at 63.7 cm. The maximum possible error in the speed of sound isa)51.2 cm/sb)102.4 cm/sc)204.8 cm/sd)153.6 cm/sCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a resonance tube with tuning fork of frequency 512 Hz, first resonance occurs at water level equal to 30.3 cm and second resonance occurs at 63.7 cm. The maximum possible error in the speed of sound isa)51.2 cm/sb)102.4 cm/sc)204.8 cm/sd)153.6 cm/sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a resonance tube with tuning fork of frequency 512 Hz, first resonance occurs at water level equal to 30.3 cm and second resonance occurs at 63.7 cm. The maximum possible error in the speed of sound isa)51.2 cm/sb)102.4 cm/sc)204.8 cm/sd)153.6 cm/sCorrect answer is option 'C'. Can you explain this answer?.
In a resonance tube with tuning fork of frequency 512 Hz, first resonance occurs at water level equal to 30.3 cm and second resonance occurs at 63.7 cm. The maximum possible error in the speed of sound isa)51.2 cm/sb)102.4 cm/sc)204.8 cm/sd)153.6 cm/sCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a resonance tube with tuning fork of frequency 512 Hz, first resonance occurs at water level equal to 30.3 cm and second resonance occurs at 63.7 cm. The maximum possible error in the speed of sound isa)51.2 cm/sb)102.4 cm/sc)204.8 cm/sd)153.6 cm/sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a resonance tube with tuning fork of frequency 512 Hz, first resonance occurs at water level equal to 30.3 cm and second resonance occurs at 63.7 cm. The maximum possible error in the speed of sound isa)51.2 cm/sb)102.4 cm/sc)204.8 cm/sd)153.6 cm/sCorrect answer is option 'C'. Can you explain this answer?.
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