when two capacitors are put in series, the equivalent capacitance isa)...
Explanation:When two capacitors C1 and C2 are connected in series, the reciprocal of the equivalent capacitance in series is equal to the sum of the reciprocals of the two individual capacitances.
It has value lesser than the least value of capacitance.
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when two capacitors are put in series, the equivalent capacitance isa)...
Explanation:
When two capacitors are put in series, the equivalent capacitance is smaller than both capacitances.
Why is this so? Let's look at the equation for capacitance in series:
1/Ceq = 1/C1 + 1/C2
Where Ceq is the equivalent capacitance and C1 and C2 are the capacitances of the individual capacitors. From this equation, we can see that the sum of the reciprocals of the capacitances is equal to the reciprocal of the equivalent capacitance.
Now, let's consider what happens when we put two capacitors in series. In this case, the capacitors share the same charge, so the voltage across each capacitor is different. This means that the capacitances are not simply added together, but rather combine in a way that reduces the overall capacitance.
To see why this is the case, let's take a simple example. Suppose we have two capacitors, each with a capacitance of 1 microfarad. If we put these capacitors in series, the equivalent capacitance is:
1/Ceq = 1/1 + 1/1 = 1/2
Ceq = 2 microfarads
As we can see, the equivalent capacitance is smaller than the capacitance of either capacitor alone. This is because the capacitors effectively "cancel out" some of each other's capacitance due to the shared charge and differing voltages.
Overall, when two capacitors are put in series, the equivalent capacitance is smaller than both capacitances because the capacitors "cancel out" some of each other's capacitance.
when two capacitors are put in series, the equivalent capacitance isa)...