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A spherical black body with a radius of 12 cm radiates 450 W power at 500 K. if the radius were halved and the temperature doubled, the power radiated in watt would be
  • a)
    255
  • b)
    450
  • c)
    900
  • d)
    1800 
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A spherical black body with a radius of 12 cm radiates 450 W power at ...
The energy radiated per second by a black body is given by Stefan's Law
Dividing (ii) and (i), we get
 
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A spherical black body with a radius of 12 cm radiates 450 W power at ...
Solution:

Given,

Radius of the black body, R1 = 12 cm

Power radiated, P1 = 450 W

Temperature, T1 = 500 K

New values,

Radius of the black body, R2 = R1/2 = 6 cm

Temperature, T2 = 2T1 = 1000 K

Let P2 be the power radiated by the black body for the new values.

We know that the power radiated by a black body is given by Stefan's law as,

P ∝ T^4 A

where P is power radiated, T is the temperature of the black body, and A is the surface area of the black body.

Now,

The surface area of the black body is given by,

A = 4πR^2

where R is the radius of the black body.

So,

P ∝ T^4 R^2

or,

P1/T1^4 R1^2 = P2/T2^4 R2^2

Substituting the given values,

450/500^4 × 12^2 = P2/1000^4 × 6^2

Simplifying,

P2 = 1800 W

Hence, the power radiated by the black body for the new values is 1800 W.

Therefore, the correct option is (D).
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A spherical black body with a radius of 12 cm radiates 450 W power at 500 K. if the radius were halved and the temperature doubled, the power radiated in watt would bea)255b)450c)900d)1800Correct answer is option 'D'. Can you explain this answer?
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