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In series RL circuit, the voltage across the resistance is 40 V and voltage across the inductance is 40 V. Then the total voltage across the series circuit is
  • a)
    40 V
  • b)
    56.56 V
  • c)
    80 V
  • d)
    5.656 V
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In series RL circuit, the voltage across the resistance is 40 V and vo...
Voltage across resistor (VR) = 40 V
Voltage across (VL) = 40 V
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Most Upvoted Answer
In series RL circuit, the voltage across the resistance is 40 V and vo...
Series RL Circuit:
A series RL circuit consists of a resistor (R) and an inductor (L) connected in series with a voltage source. The voltage across the resistor and the voltage across the inductor can be different due to the reactance of the inductor.

Given Information:
Voltage across the resistance (VR) = 40 V
Voltage across the inductance (VL) = 40 V

Total Voltage across the Series Circuit:
The total voltage across the series circuit is the sum of the voltage across the resistor and the voltage across the inductor.

Total Voltage (VT) = VR + VL

Explanation:
Given that the voltage across the resistance is 40 V and the voltage across the inductance is also 40 V. Since both the voltages are equal, the reactance of the inductor must be equal to the resistance.

Reactance of an inductor (XL) = VL / I

Where I is the current flowing through the circuit. Since the resistance is equal to the reactance of the inductor, the current flowing through the circuit can be calculated using Ohm's Law.

Current (I) = VR / R

Substituting the values:

I = 40 V / R

Now, substituting the value of current in the reactance formula:

XL = VL / (40 V / R)

Since XL = R, we can equate the two equations:

R = VL / (40 V / R)

Simplifying the equation:

R^2 = VL * R / 40 V

R = VL / 40 V

Now, substituting the value of R in the equation for current:

I = 40 V / (VL / 40 V)

Simplifying:

I = 1600 V / VL

Since the voltage across the inductor is given as 40 V, we can calculate the current using the above equation:

I = 1600 V / 40 V = 40 A

Finally, substituting the values of VR, VL, and I in the equation for total voltage:

VT = VR + VL
= 40 V + 40 V
= 80 V

Therefore, the total voltage across the series circuit is 80 V.
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In series RL circuit, the voltage across the resistance is 40 V and voltage across the inductance is 40 V. Then the total voltage across the series circuit isa)40 Vb)56.56 Vc)80 Vd)5.656 VCorrect answer is option 'B'. Can you explain this answer?
Question Description
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