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Two electric bulbs, one of 200 V, 40W and otherof 200 V, 100W are connected in a domesticcircuit. Then [2000]
  • a)
    they have equal resistance
  • b)
    the resistance of 40W bulb is more than100W bulb
  • c)
    the resistance of 100W bulb is more than 40W bulb
  • d)
    they have equal current through them
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Two electric bulbs, one of 200 V, 40W and otherof 200 V, 100W are conn...
∴ R1 (for 40W) > R2 (for 100 W)
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Most Upvoted Answer
Two electric bulbs, one of 200 V, 40W and otherof 200 V, 100W are conn...
Explanation:

Electric power is given by P = VI. Hence, we can calculate the resistance using Ohm's Law as follows:

R = V^2/P

For the 40W bulb:

Resistance R1 = (200V)^2/40W = 1000 ohms

For the 100W bulb:

Resistance R2 = (200V)^2/100W = 400 ohms

Therefore, the resistance of the 40W bulb is more than the 100W bulb.

Hence, the correct option is B.

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Explanation:


  • Electric power is given by P = VI.

  • We can calculate the resistance using Ohm's Law as follows: R = V^2/P

  • For the 40W bulb: Resistance R1 = (200V)^2/40W = 1000 ohms

  • For the 100W bulb: Resistance R2 = (200V)^2/100W = 400 ohms

  • Therefore, the resistance of the 40W bulb is more than the 100W bulb.

  • Hence, the correct option is B.

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Two electric bulbs, one of 200 V, 40W and otherof 200 V, 100W are connected in a domesticcircuit. Then [2000]a)they have equal resistanceb)the resistance of 40W bulb is more than100W bulbc)the resistance of 100W bulb is more than 40W bulbd)they have equal current through themCorrect answer is option 'B'. Can you explain this answer?
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