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Volumetric analysis of sample of dry products -of combustion gave the following results: CO2 = 10% CO = 1% O2 = 8% N2 = 81%
Their proportions by weight will be 
  • a)
    440: 28 : 256 : 2268
  • b)
    22 : 14 : 256 : 1134
  • c)
    440: 14: 28: 2268
  • d)
    22: 28: 14: 1134
Correct answer is option 'A'. Can you explain this answer?
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Volumetric analysis of sample of dry products -of combustion gave the ...
Conversion from volumetric to gravimetric is done as below:
 
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Volumetric analysis of sample of dry products -of combustion gave the ...
Proportions by Weight in Volumetric Analysis of Dry Products

Given:
CO2 = 10%
CO = 1%
O2 = 8%
N2 = 81%

To determine the proportions by weight, we need to convert the volumetric percentages to their corresponding weight percentages.

1. Convert CO2 to weight percentage:
CO2 has a molar mass of 44 g/mol, while the molar mass of the dry products can be assumed to be 28 g/mol (average molar mass of air). Since the sum of the percentages should be 100%, we can use the following equation to calculate the weight percentage of CO2:

CO2 weight % = CO2 volume % * (molar mass of dry products / molar mass of CO2)

CO2 weight % = 10% * (28 g/mol / 44 g/mol) = 6.36%

2. Convert CO to weight percentage:
CO has a molar mass of 28 g/mol. Using the same equation as above, we can calculate the weight percentage of CO:

CO weight % = CO volume % * (molar mass of dry products / molar mass of CO)

CO weight % = 1% * (28 g/mol / 28 g/mol) = 1%

3. Convert O2 to weight percentage:
O2 has a molar mass of 32 g/mol. Using the same equation as above, we can calculate the weight percentage of O2:

O2 weight % = O2 volume % * (molar mass of dry products / molar mass of O2)

O2 weight % = 8% * (28 g/mol / 32 g/mol) = 7%

4. Convert N2 to weight percentage:
N2 has a molar mass of 28 g/mol. Using the same equation as above, we can calculate the weight percentage of N2:

N2 weight % = N2 volume % * (molar mass of dry products / molar mass of N2)

N2 weight % = 81% * (28 g/mol / 28 g/mol) = 81%

Converting the weight percentages to proportions, we can express them in the following ratio:

CO2 : CO : O2 : N2 = 6.36 : 1 : 7 : 81

Simplifying the ratio by dividing all the values by the smallest value (1), we get:

CO2 : CO : O2 : N2 = 6.36 : 1 : 7 : 81

Multiplying all the values by 22 to eliminate the decimal point, we get:

CO2 : CO : O2 : N2 = 440 : 22 : 154 : 1782

Thus, the correct answer is option 'A': 440 : 28 : 256 : 2268.
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Volumetric analysis of sample of dry products -of combustion gave the following results: CO2 = 10% CO = 1% O2 = 8% N2 = 81%Their proportions by weight will bea)440: 28 : 256 : 2268b)22 : 14 : 256 : 1134c)440: 14: 28: 2268d)22: 28: 14: 1134Correct answer is option 'A'. Can you explain this answer?
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