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The mass of air required for complete combustion of unit mass of fuel canalways be calculated from the formula, where C, H, O and S are inpercentage.
- a)0.1152C + 0.3456H
- b)0.1152C + 0.3456 (H - 0.125 O)
- c)O.1152C + 0.3456 (H - 0.125 O) + 0.0432S
- d)0.1152C + 0.3456 (H + 0.125) + 0.0432S.
Correct answer is option 'C'. Can you explain this answer?
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The mass of air required for complete combustion of unit mass of fuel ...
Mass of air for complete combustion is 0.1152C + 0.3456 (H - 0.125 O) + 0.0432 S.
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The mass of air required for complete combustion of unit mass of fuel ...
To calculate the mass of air required for complete combustion of a unit mass of fuel, we need to consider the percentage composition of carbon (C), hydrogen (H), oxygen (O), and sulfur (S) in the fuel. The correct formula for calculating the mass of air is given by option C: 0.1152C + 0.3456(H - 0.125O) + 0.0432S.
Explanation:
1. The percentage composition of carbon (C), hydrogen (H), oxygen (O), and sulfur (S) in the fuel is given in percentages. We need to convert these percentages to decimal form before using them in the formula.
2. The first term in the formula, 0.1152C, represents the mass of air required for the combustion of carbon. This term accounts for the oxygen required to convert carbon into carbon dioxide (CO2) during combustion.
3. The second term, 0.3456(H - 0.125O), represents the mass of air required for the combustion of hydrogen. This term takes into account the fact that hydrogen in the fuel combines with oxygen to form water vapor (H2O) during combustion. Since each molecule of water contains two hydrogen atoms and one oxygen atom, we subtract 0.125 times the percentage of oxygen from the percentage of hydrogen to account for the stoichiometric ratio.
4. The third term, 0.0432S, represents the mass of air required for the combustion of sulfur. This term accounts for the oxygen required to convert sulfur into sulfur dioxide (SO2) during combustion.
5. By summing up these terms, we get the total mass of air required for the complete combustion of a unit mass of fuel.
Option C provides the correct formula that accounts for the combustion of carbon, hydrogen, oxygen, and sulfur in the fuel. The other options do not consider the correct stoichiometric ratios for the combustion reactions. Therefore, option C is the correct answer.
Explanation:
1. The percentage composition of carbon (C), hydrogen (H), oxygen (O), and sulfur (S) in the fuel is given in percentages. We need to convert these percentages to decimal form before using them in the formula.
2. The first term in the formula, 0.1152C, represents the mass of air required for the combustion of carbon. This term accounts for the oxygen required to convert carbon into carbon dioxide (CO2) during combustion.
3. The second term, 0.3456(H - 0.125O), represents the mass of air required for the combustion of hydrogen. This term takes into account the fact that hydrogen in the fuel combines with oxygen to form water vapor (H2O) during combustion. Since each molecule of water contains two hydrogen atoms and one oxygen atom, we subtract 0.125 times the percentage of oxygen from the percentage of hydrogen to account for the stoichiometric ratio.
4. The third term, 0.0432S, represents the mass of air required for the combustion of sulfur. This term accounts for the oxygen required to convert sulfur into sulfur dioxide (SO2) during combustion.
5. By summing up these terms, we get the total mass of air required for the complete combustion of a unit mass of fuel.
Option C provides the correct formula that accounts for the combustion of carbon, hydrogen, oxygen, and sulfur in the fuel. The other options do not consider the correct stoichiometric ratios for the combustion reactions. Therefore, option C is the correct answer.
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The mass of air required for complete combustion of unit mass of fuel canalways be calculated from the formula, where C, H, O and S are inpercentage.a)0.1152C + 0.3456Hb)0.1152C + 0.3456 (H - 0.125 O)c)O.1152C + 0.3456 (H - 0.125 O) + 0.0432Sd)0.1152C + 0.3456 (H + 0.125) + 0.0432S.Correct answer is option 'C'. Can you explain this answer?
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