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Three masses of 500 g, 300 g and 100 g are suspended at the end of an ideal  spring as shown and are in equilibrium. When the 500 g mass is suddenly removed, the system oscillated with a period of 2 s. When 300 g mass is also removed, it will oscillate with the period
  • a)
    1.75 s
  • b)
    1.25 s 
  • c)
    1.5 s
  • d)
    1 s 
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Three masses of 500 g, 300 g and 100 g are suspended at the end of an ...
When 500 g is removed, m = (100 + 300)g = 0.4 kg 
When 300 g is also removed, 
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Three masses of 500 g, 300 g and 100 g are suspended at the end of an ...
The period of oscillation of a mass-spring system is determined by the mass of the object and the spring constant. In this case, we have three masses suspended at the end of an ideal spring. Let's analyze the situation step by step.

First, when all three masses (500 g, 300 g, and 100 g) are in equilibrium, the system is balanced, and the spring is neither stretched nor compressed. The total mass of the system is 900 g (500 g + 300 g + 100 g).

When the 500 g mass is suddenly removed, the total mass of the system becomes 400 g (300 g + 100 g). The removal of the 500 g mass causes a change in the equilibrium position of the system, and it starts to oscillate. The period of oscillation is given as 2 s.

To find the period when the 300 g mass is also removed, we need to consider the change in the total mass of the system. When the 300 g mass is removed, the total mass becomes 100 g (100 g). Since the 500 g mass has already been removed, the remaining masses have a total mass of 100 g.

The period of oscillation of a mass-spring system is inversely proportional to the square root of the total mass. Mathematically, we can express this relationship as:

T ∝ 1/√m

Where T is the period of oscillation and m is the total mass of the system.

Since the total mass becomes 100 g when the 300 g mass is removed, the period of oscillation will be:

T ∝ 1/√100 = 1/10 = 0.1 s

However, the given options are in seconds, so we need to convert 0.1 s to the desired unit. 0.1 s is equal to 1 s, which corresponds to option D.

Therefore, when the 300 g mass is also removed, the system will oscillate with a period of 1 s.
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Three masses of 500 g, 300 g and 100 g are suspended at the end of an ideal spring as shown and are in equilibrium. When the 500 g mass is suddenly removed, the system oscillated with a period of 2 s. When 300 g mass is also removed, it will oscillate with the perioda)1.75 sb)1.25 sc)1.5 sd)1 sCorrect answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Three masses of 500 g, 300 g and 100 g are suspended at the end of an ideal spring as shown and are in equilibrium. When the 500 g mass is suddenly removed, the system oscillated with a period of 2 s. When 300 g mass is also removed, it will oscillate with the perioda)1.75 sb)1.25 sc)1.5 sd)1 sCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Three masses of 500 g, 300 g and 100 g are suspended at the end of an ideal spring as shown and are in equilibrium. When the 500 g mass is suddenly removed, the system oscillated with a period of 2 s. When 300 g mass is also removed, it will oscillate with the perioda)1.75 sb)1.25 sc)1.5 sd)1 sCorrect answer is option 'D'. Can you explain this answer?.
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