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For a steady flow process from state 1 to 2, enthalpy changes from h1 = 400 kJ/kg to h2 = 100 kJ/kg and entropy changes from s1 = 1.1 kJ/kg-K to s2 = 0.7 kJ/kg-K. Surrounding environmental temperature is 300 K. Neglect changes in kinetic and potential energy. The change in availability of the system is:
- a)420 kJ/kg
- b)300 kJ/kg
- c)180 kJ/kg
- d)90 kJ/kg
Correct answer is option 'C'. Can you explain this answer?
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For a steady flow process from state 1 to 2, enthalpy changes from h1 ...
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For a steady flow process from state 1 to 2, enthalpy changes from h1 ...
Given data:
h1 = 400 kJ/kg
h2 = 100 kJ/kg
s1 = 1.1 kJ/kg-K
s2 = 0.7 kJ/kg-K
T = 300 K
We are required to calculate the change in availability of the system.
Availability, also known as exergy, is a measure of the useful work that can be extracted from a system. It is given by the equation:
A = h - Ts
where A is the availability, h is the enthalpy, T is the temperature, and s is the entropy.
Step 1: Calculate the availability at state 1
A1 = h1 - T * s1
A1 = 400 - 300 * 1.1
A1 = 70 kJ/kg
Step 2: Calculate the availability at state 2
A2 = h2 - T * s2
A2 = 100 - 300 * 0.7
A2 = -110 kJ/kg
Step 3: Calculate the change in availability
ΔA = A2 - A1
ΔA = -110 - 70
ΔA = -180 kJ/kg
The negative sign indicates that the availability of the system has decreased. However, the question asks for the absolute value of the change in availability, so we take the absolute value:
|ΔA| = |-180| = 180 kJ/kg
Therefore, the correct answer is option C) 180 kJ/kg.
h1 = 400 kJ/kg
h2 = 100 kJ/kg
s1 = 1.1 kJ/kg-K
s2 = 0.7 kJ/kg-K
T = 300 K
We are required to calculate the change in availability of the system.
Availability, also known as exergy, is a measure of the useful work that can be extracted from a system. It is given by the equation:
A = h - Ts
where A is the availability, h is the enthalpy, T is the temperature, and s is the entropy.
Step 1: Calculate the availability at state 1
A1 = h1 - T * s1
A1 = 400 - 300 * 1.1
A1 = 70 kJ/kg
Step 2: Calculate the availability at state 2
A2 = h2 - T * s2
A2 = 100 - 300 * 0.7
A2 = -110 kJ/kg
Step 3: Calculate the change in availability
ΔA = A2 - A1
ΔA = -110 - 70
ΔA = -180 kJ/kg
The negative sign indicates that the availability of the system has decreased. However, the question asks for the absolute value of the change in availability, so we take the absolute value:
|ΔA| = |-180| = 180 kJ/kg
Therefore, the correct answer is option C) 180 kJ/kg.
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For a steady flow process from state 1 to 2, enthalpy changes from h1 = 400 kJ/kg to h2 = 100 kJ/kg and entropy changes from s1 = 1.1 kJ/kg-K to s2 = 0.7 kJ/kg-K. Surrounding environmental temperature is 300 K. Neglect changes in kinetic and potential energy. The change in availability of the system is:a)420 kJ/kgb)300 kJ/kgc)180 kJ/kgd)90 kJ/kgCorrect answer is option 'C'. Can you explain this answer?
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For a steady flow process from state 1 to 2, enthalpy changes from h1 = 400 kJ/kg to h2 = 100 kJ/kg and entropy changes from s1 = 1.1 kJ/kg-K to s2 = 0.7 kJ/kg-K. Surrounding environmental temperature is 300 K. Neglect changes in kinetic and potential energy. The change in availability of the system is:a)420 kJ/kgb)300 kJ/kgc)180 kJ/kgd)90 kJ/kgCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about For a steady flow process from state 1 to 2, enthalpy changes from h1 = 400 kJ/kg to h2 = 100 kJ/kg and entropy changes from s1 = 1.1 kJ/kg-K to s2 = 0.7 kJ/kg-K. Surrounding environmental temperature is 300 K. Neglect changes in kinetic and potential energy. The change in availability of the system is:a)420 kJ/kgb)300 kJ/kgc)180 kJ/kgd)90 kJ/kgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a steady flow process from state 1 to 2, enthalpy changes from h1 = 400 kJ/kg to h2 = 100 kJ/kg and entropy changes from s1 = 1.1 kJ/kg-K to s2 = 0.7 kJ/kg-K. Surrounding environmental temperature is 300 K. Neglect changes in kinetic and potential energy. The change in availability of the system is:a)420 kJ/kgb)300 kJ/kgc)180 kJ/kgd)90 kJ/kgCorrect answer is option 'C'. Can you explain this answer?.
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