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The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg What will be the value of latent heat of vaporization using Clausius Clapeyron equation?
- a)16000 kJ/kg
- b)1600 kJ/kg
- c)1000 kJ/kg
- d)160 kJ/kg
Correct answer is option 'C'. Can you explain this answer?
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Given data:
Saturation temperature, T = 400 K
Variation of saturation pressure with saturation temperature, dP/dT = 0.1 bar/K
Specific volume of saturated liquid, v_f = 0.251 m^3/kg
Specific volume of dry saturated vapor, v_g = 0.001 m^3/kg
Explanation:
The Clausius-Clapeyron equation relates the variation of saturation pressure with saturation temperature to the latent heat of vaporization. It is given by:
dP/dT = ΔH_vap / (v_g - v_f)
where ΔH_vap is the latent heat of vaporization, v_g is the specific volume of dry saturated vapor, and v_f is the specific volume of saturated liquid.
Calculating the latent heat of vaporization:
We are given that dP/dT = 0.1 bar/K. To convert this to SI units, we convert bar to Pa:
0.1 bar = 10^4 Pa
Substituting the given values into the Clausius-Clapeyron equation:
10^4 Pa = ΔH_vap / (0.001 m^3/kg - 0.251 m^3/kg)
Simplifying the equation:
10^4 Pa = ΔH_vap / (-0.25 m^3/kg)
Rearranging the equation to solve for ΔH_vap:
ΔH_vap = 10^4 Pa * (-0.25 m^3/kg)
Converting Pa to kPa:
ΔH_vap = 10^4 kPa * (-0.25 m^3/kg)
ΔH_vap = -2500 kJ/kg
Since the latent heat of vaporization is a positive quantity, we take the magnitude of the value:
ΔH_vap = 2500 kJ/kg
Therefore, the value of the latent heat of vaporization using the Clausius-Clapeyron equation is 2500 kJ/kg. However, the correct answer option is 1000 kJ/kg. This suggests that there might be a mistake or discrepancy in the given data or calculation.
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The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg What will be the value of latent heat of vaporization using Clausius Clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kJ/kgCorrect answer is option 'C'. Can you explain this answer?
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The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg What will be the value of latent heat of vaporization using Clausius Clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kJ/kgCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg What will be the value of latent heat of vaporization using Clausius Clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kJ/kgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg What will be the value of latent heat of vaporization using Clausius Clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kJ/kgCorrect answer is option 'C'. Can you explain this answer?.
The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg What will be the value of latent heat of vaporization using Clausius Clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kJ/kgCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg What will be the value of latent heat of vaporization using Clausius Clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kJ/kgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The variation of saturation pressure with saturation temperature for a liquid is 0.1 bar/K at 400 K. The specific volume of saturated liquid and dry saturated vapour at 400 K are 0.251 and 0.001 m3/kg What will be the value of latent heat of vaporization using Clausius Clapeyron equation?a)16000 kJ/kgb)1600 kJ/kgc)1000 kJ/kgd)160 kJ/kgCorrect answer is option 'C'. Can you explain this answer?.
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