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Resistance of conductivity cell Filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm the conductivity of the solution is 1.29 S /m resistance of the same cell when filled with 0.02 M of the same solution is 520 ohm the molar conductivity of 0.02 M solution of electrolyte will be?
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Resistance of conductivity cell Filled with a solution of an electroly...
Calculation of Molar Conductivity of 0.02 M solution of electrolyte
Given Data:
Calculation:
The resistance of the conductivity cell filled with a solution of electrolyte is inversely proportional to the conductivity of the solution. Therefore, we can write the following equation:
R = (1/κ) x k
where R is the resistance of the conductivity cell, κ is the conductivity of the solution, and k is a constant.
Calculation for 0.1 M solution:
Using the above equation, we can find the value of k for the 0.1 M solution as follows:
100 = (1/1.29) x k
k = 129
Now, we can use this value of k to find the conductivity of the 0.02 M solution as follows:
Calculation for 0.02 M solution:
520 = (1/κ) x 129
κ = 0.025 S/m
The molar conductivity of a solution can be calculated by dividing the conductivity of the solution by the concentration of the electrolyte. Therefore, we can find the molar conductivity of the 0.02 M solution as follows:
Molar Conductivity of 0.02 M solution:
Molar conductivity = κ / c
where c is the concentration of the electrolyte.
Molar conductivity = 0.025 / 0.02
Molar conductivity = 1.25 S m² mol⁻¹
Therefore, the molar conductivity of the 0.02 M solution of electrolyte is 1.25 S m² mol⁻¹.
Given Data:
- Resistance of conductivity cell filled with 0.1 M solution = 100 ohm
- Conductivity of 0.1 M solution = 1.29 S/m
- Resistance of conductivity cell filled with 0.02 M solution = 520 ohm
Calculation:
The resistance of the conductivity cell filled with a solution of electrolyte is inversely proportional to the conductivity of the solution. Therefore, we can write the following equation:
R = (1/κ) x k
where R is the resistance of the conductivity cell, κ is the conductivity of the solution, and k is a constant.
Calculation for 0.1 M solution:
Using the above equation, we can find the value of k for the 0.1 M solution as follows:
100 = (1/1.29) x k
k = 129
Now, we can use this value of k to find the conductivity of the 0.02 M solution as follows:
Calculation for 0.02 M solution:
520 = (1/κ) x 129
κ = 0.025 S/m
The molar conductivity of a solution can be calculated by dividing the conductivity of the solution by the concentration of the electrolyte. Therefore, we can find the molar conductivity of the 0.02 M solution as follows:
Molar Conductivity of 0.02 M solution:
Molar conductivity = κ / c
where c is the concentration of the electrolyte.
Molar conductivity = 0.025 / 0.02
Molar conductivity = 1.25 S m² mol⁻¹
Therefore, the molar conductivity of the 0.02 M solution of electrolyte is 1.25 S m² mol⁻¹.
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Resistance of conductivity cell Filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm the conductivity of the solution is 1.29 S /m resistance of the same cell when filled with 0.02 M of the same solution is 520 ohm the molar conductivity of 0.02 M solution of electrolyte will be?
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Resistance of conductivity cell Filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm the conductivity of the solution is 1.29 S /m resistance of the same cell when filled with 0.02 M of the same solution is 520 ohm the molar conductivity of 0.02 M solution of electrolyte will be? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Resistance of conductivity cell Filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm the conductivity of the solution is 1.29 S /m resistance of the same cell when filled with 0.02 M of the same solution is 520 ohm the molar conductivity of 0.02 M solution of electrolyte will be? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Resistance of conductivity cell Filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm the conductivity of the solution is 1.29 S /m resistance of the same cell when filled with 0.02 M of the same solution is 520 ohm the molar conductivity of 0.02 M solution of electrolyte will be?.
Resistance of conductivity cell Filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm the conductivity of the solution is 1.29 S /m resistance of the same cell when filled with 0.02 M of the same solution is 520 ohm the molar conductivity of 0.02 M solution of electrolyte will be? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Resistance of conductivity cell Filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm the conductivity of the solution is 1.29 S /m resistance of the same cell when filled with 0.02 M of the same solution is 520 ohm the molar conductivity of 0.02 M solution of electrolyte will be? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Resistance of conductivity cell Filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm the conductivity of the solution is 1.29 S /m resistance of the same cell when filled with 0.02 M of the same solution is 520 ohm the molar conductivity of 0.02 M solution of electrolyte will be?.
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