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When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.
Q. If r = 5 × 10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximately
- a)1.4 × 10–3m
- b)3.3 × 10–3m
- c)2.0 × 10–3m
- d)4.1 × 10–3 m
Correct answer is option 'A'. Can you explain this answer?
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When liquid medicine of density ρ is to put in the eye, it is done...
When the drop is about to detach from the dropper Weight = vertical force due to surface tension
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When liquid medicine of density ρ is to put in the eye, it is done...
Ρ1 is added to a container of liquid of density ρ2, the resulting density of the mixture can be calculated using the following formula:
ρm = (m1ρ1 + m2ρ2) / (m1 + m2)
where ρm is the density of the resulting mixture, m1 is the mass of the first liquid added, m2 is the mass of the second liquid added, ρ1 is the density of the first liquid, and ρ2 is the density of the second liquid.
Note that this formula assumes that the liquids are completely miscible, meaning they can be mixed together without separating into distinct layers. If the liquids are immiscible, the resulting mixture will have distinct layers with different densities.
ρm = (m1ρ1 + m2ρ2) / (m1 + m2)
where ρm is the density of the resulting mixture, m1 is the mass of the first liquid added, m2 is the mass of the second liquid added, ρ1 is the density of the first liquid, and ρ2 is the density of the second liquid.
Note that this formula assumes that the liquids are completely miscible, meaning they can be mixed together without separating into distinct layers. If the liquids are immiscible, the resulting mixture will have distinct layers with different densities.
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When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.Q.If r = 5 ×10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximatelya)1.4 × 10–3mb)3.3 × 10–3mc)2.0 × 10–3md)4.1 × 10–3 mCorrect answer is option 'A'. Can you explain this answer?
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When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.Q.If r = 5 ×10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximatelya)1.4 × 10–3mb)3.3 × 10–3mc)2.0 × 10–3md)4.1 × 10–3 mCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.Q.If r = 5 ×10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximatelya)1.4 × 10–3mb)3.3 × 10–3mc)2.0 × 10–3md)4.1 × 10–3 mCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.Q.If r = 5 ×10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximatelya)1.4 × 10–3mb)3.3 × 10–3mc)2.0 × 10–3md)4.1 × 10–3 mCorrect answer is option 'A'. Can you explain this answer?.
When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.Q.If r = 5 ×10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximatelya)1.4 × 10–3mb)3.3 × 10–3mc)2.0 × 10–3md)4.1 × 10–3 mCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.Q.If r = 5 ×10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximatelya)1.4 × 10–3mb)3.3 × 10–3mc)2.0 × 10–3md)4.1 × 10–3 mCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.Q.If r = 5 ×10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximatelya)1.4 × 10–3mb)3.3 × 10–3mc)2.0 × 10–3md)4.1 × 10–3 mCorrect answer is option 'A'. Can you explain this answer?.
Solutions for When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.Q.If r = 5 ×10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximatelya)1.4 × 10–3mb)3.3 × 10–3mc)2.0 × 10–3md)4.1 × 10–3 mCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.Q.If r = 5 ×10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximatelya)1.4 × 10–3mb)3.3 × 10–3mc)2.0 × 10–3md)4.1 × 10–3 mCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.Q.If r = 5 ×10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximatelya)1.4 × 10–3mb)3.3 × 10–3mc)2.0 × 10–3md)4.1 × 10–3 mCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.Q.If r = 5 ×10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximatelya)1.4 × 10–3mb)3.3 × 10–3mc)2.0 × 10–3md)4.1 × 10–3 mCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.Q.If r = 5 ×10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximatelya)1.4 × 10–3mb)3.3 × 10–3mc)2.0 × 10–3md)4.1 × 10–3 mCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice When liquid medicine of density ρ is to put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper.Q.If r = 5 ×10–4 m, ρ = 103 kgm–3 , g = 10 ms–2 ,T= 0.11Nm –1, the radius of the drop when it detaches from the dropper is approximatelya)1.4 × 10–3mb)3.3 × 10–3mc)2.0 × 10–3md)4.1 × 10–3 mCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
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