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Paragraphs for Question 12 To 14When liquid medicine of density ρ is to be put in the eye, it is done with the help of a dropper. As the bulb on thetop of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop.We first assume that the drop formed at the opening is spherical because that requires a minimum increase in itssurface energy. To determine the size, we calculate the net vertical force due to the surface tension T when theradius of the drop is R. When the force becomes smaller than the weight of the drop, the drop gets detached from thedropper.Q.If r = 5 × 10−4 m, ρ = 103 kg m−3, g = 10 m/s2, T = 0.11 Nm−1, the radius of the drop when it detaches fromthe dropper is approximatelya)1.4 × 10−3 mb)3.3 × 10−3 mc)2.0 × 10−3 md)4.1 × 10−3 mCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Paragraphs for Question 12 To 14When liquid medicine of density ρ is to be put in the eye, it is done with the help of a dropper. As the bulb on thetop of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop.We first assume that the drop formed at the opening is spherical because that requires a minimum increase in itssurface energy. To determine the size, we calculate the net vertical force due to the surface tension T when theradius of the drop is R. When the force becomes smaller than the weight of the drop, the drop gets detached from thedropper.Q.If r = 5 × 10−4 m, ρ = 103 kg m−3, g = 10 m/s2, T = 0.11 Nm−1, the radius of the drop when it detaches fromthe dropper is approximatelya)1.4 × 10−3 mb)3.3 × 10−3 mc)2.0 × 10−3 md)4.1 × 10−3 mCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Paragraphs for Question 12 To 14When liquid medicine of density ρ is to be put in the eye, it is done with the help of a dropper. As the bulb on thetop of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop.We first assume that the drop formed at the opening is spherical because that requires a minimum increase in itssurface energy. To determine the size, we calculate the net vertical force due to the surface tension T when theradius of the drop is R. When the force becomes smaller than the weight of the drop, the drop gets detached from thedropper.Q.If r = 5 × 10−4 m, ρ = 103 kg m−3, g = 10 m/s2, T = 0.11 Nm−1, the radius of the drop when it detaches fromthe dropper is approximatelya)1.4 × 10−3 mb)3.3 × 10−3 mc)2.0 × 10−3 md)4.1 × 10−3 mCorrect answer is option 'A'. Can you explain this answer?.

Solutions for Paragraphs for Question 12 To 14When liquid medicine of density ρ is to be put in the eye, it is done with the help of a dropper. As the bulb on thetop of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop.We first assume that the drop formed at the opening is spherical because that requires a minimum increase in itssurface energy. To determine the size, we calculate the net vertical force due to the surface tension T when theradius of the drop is R. When the force becomes smaller than the weight of the drop, the drop gets detached from thedropper.Q.If r = 5 × 10−4 m, ρ = 103 kg m−3, g = 10 m/s2, T = 0.11 Nm−1, the radius of the drop when it detaches fromthe dropper is approximatelya)1.4 × 10−3 mb)3.3 × 10−3 mc)2.0 × 10−3 md)4.1 × 10−3 mCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Paragraphs for Question 12 To 14When liquid medicine of density ρ is to be put in the eye, it is done with the help of a dropper. As the bulb on thetop of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop.We first assume that the drop formed at the opening is spherical because that requires a minimum increase in itssurface energy. To determine the size, we calculate the net vertical force due to the surface tension T when theradius of the drop is R. When the force becomes smaller than the weight of the drop, the drop gets detached from thedropper.Q.If r = 5 × 10−4 m, ρ = 103 kg m−3, g = 10 m/s2, T = 0.11 Nm−1, the radius of the drop when it detaches fromthe dropper is approximatelya)1.4 × 10−3 mb)3.3 × 10−3 mc)2.0 × 10−3 md)4.1 × 10−3 mCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Paragraphs for Question 12 To 14When liquid medicine of density ρ is to be put in the eye, it is done with the help of a dropper. As the bulb on thetop of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop.We first assume that the drop formed at the opening is spherical because that requires a minimum increase in itssurface energy. To determine the size, we calculate the net vertical force due to the surface tension T when theradius of the drop is R. When the force becomes smaller than the weight of the drop, the drop gets detached from thedropper.Q.If r = 5 × 10−4 m, ρ = 103 kg m−3, g = 10 m/s2, T = 0.11 Nm−1, the radius of the drop when it detaches fromthe dropper is approximatelya)1.4 × 10−3 mb)3.3 × 10−3 mc)2.0 × 10−3 md)4.1 × 10−3 mCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Paragraphs for Question 12 To 14When liquid medicine of density ρ is to be put in the eye, it is done with the help of a dropper. As the bulb on thetop of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop.We first assume that the drop formed at the opening is spherical because that requires a minimum increase in itssurface energy. To determine the size, we calculate the net vertical force due to the surface tension T when theradius of the drop is R. When the force becomes smaller than the weight of the drop, the drop gets detached from thedropper.Q.If r = 5 × 10−4 m, ρ = 103 kg m−3, g = 10 m/s2, T = 0.11 Nm−1, the radius of the drop when it detaches fromthe dropper is approximatelya)1.4 × 10−3 mb)3.3 × 10−3 mc)2.0 × 10−3 md)4.1 × 10−3 mCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Paragraphs for Question 12 To 14When liquid medicine of density ρ is to be put in the eye, it is done with the help of a dropper. As the bulb on thetop of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop.We first assume that the drop formed at the opening is spherical because that requires a minimum increase in itssurface energy. To determine the size, we calculate the net vertical force due to the surface tension T when theradius of the drop is R. When the force becomes smaller than the weight of the drop, the drop gets detached from thedropper.Q.If r = 5 × 10−4 m, ρ = 103 kg m−3, g = 10 m/s2, T = 0.11 Nm−1, the radius of the drop when it detaches fromthe dropper is approximatelya)1.4 × 10−3 mb)3.3 × 10−3 mc)2.0 × 10−3 md)4.1 × 10−3 mCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Paragraphs for Question 12 To 14When liquid medicine of density ρ is to be put in the eye, it is done with the help of a dropper. As the bulb on thetop of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop.We first assume that the drop formed at the opening is spherical because that requires a minimum increase in itssurface energy. To determine the size, we calculate the net vertical force due to the surface tension T when theradius of the drop is R. When the force becomes smaller than the weight of the drop, the drop gets detached from thedropper.Q.If r = 5 × 10−4 m, ρ = 103 kg m−3, g = 10 m/s2, T = 0.11 Nm−1, the radius of the drop when it detaches fromthe dropper is approximatelya)1.4 × 10−3 mb)3.3 × 10−3 mc)2.0 × 10−3 md)4.1 × 10−3 mCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.