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Calculate the safe stopping sight distance for a design speed of 60 km/h for two-way traffic on a single lane road. The reaction time of driver is 2.5 sec.
- a)82.21
- b)136.23
- c)164.42
- d)674.24
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Calculate the safe stopping sight distance for a design speed of 60 km...
For one-way traffic, SSD is given by:
Where,
f = coefficient of longitudinal friction = 0.35
g = acceleration due to gravity
V = Design speed = 60 Kmph = 0.278 × 60 m/s
Now for two-way traffic,
SSD required = 2 × SSD = 2 × 82.20 = 164.40 m
Most Upvoted Answer
Calculate the safe stopping sight distance for a design speed of 60 km...
Safe stopping sight distance is the distance required for a driver to bring the vehicle to a stop after he observes an object on the road. It is calculated based on the design speed of the road and the reaction time of the driver.
Given data:
Design speed = 60 km/h
Reaction time = 2.5 sec
Calculation:
1. Reaction distance:
Reaction distance is the distance travelled by the vehicle during the driver's reaction time.
Reaction distance = Design speed x Reaction time
= (60 x 1000)/3600 x 2.5
= 41.67 meters
2. Braking distance:
Braking distance is the distance travelled by the vehicle after the driver applies the brakes until it comes to a stop.
Braking distance = (v^2)/(2 x g x f)
where,
v = design speed in m/s = 60 x 1000/3600 = 16.67 m/s
g = acceleration due to gravity = 9.81 m/s^2
f = coefficient of friction between the road surface and the vehicle tires. It is assumed to be 0.4 for dry roads.
Braking distance = (16.67^2)/(2 x 9.81 x 0.4)
= 122.75 meters
3. Safe stopping sight distance:
Safe stopping sight distance = Reaction distance + Braking distance
= 41.67 + 122.75
= 164.42 meters
Therefore, the safe stopping sight distance for a design speed of 60 km/h for two-way traffic on a single lane road with a reaction time of 2.5 sec is 164.42 meters.
Given data:
Design speed = 60 km/h
Reaction time = 2.5 sec
Calculation:
1. Reaction distance:
Reaction distance is the distance travelled by the vehicle during the driver's reaction time.
Reaction distance = Design speed x Reaction time
= (60 x 1000)/3600 x 2.5
= 41.67 meters
2. Braking distance:
Braking distance is the distance travelled by the vehicle after the driver applies the brakes until it comes to a stop.
Braking distance = (v^2)/(2 x g x f)
where,
v = design speed in m/s = 60 x 1000/3600 = 16.67 m/s
g = acceleration due to gravity = 9.81 m/s^2
f = coefficient of friction between the road surface and the vehicle tires. It is assumed to be 0.4 for dry roads.
Braking distance = (16.67^2)/(2 x 9.81 x 0.4)
= 122.75 meters
3. Safe stopping sight distance:
Safe stopping sight distance = Reaction distance + Braking distance
= 41.67 + 122.75
= 164.42 meters
Therefore, the safe stopping sight distance for a design speed of 60 km/h for two-way traffic on a single lane road with a reaction time of 2.5 sec is 164.42 meters.
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Calculate the safe stopping sight distance for a design speed of 60 km...
164.388 m
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Calculate the safe stopping sight distance for a design speed of 60 km/h for two-way traffic on a single lane road. The reaction time of driver is 2.5 sec.a)82.21b)136.23c)164.42d)674.24Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Calculate the safe stopping sight distance for a design speed of 60 km/h for two-way traffic on a single lane road. The reaction time of driver is 2.5 sec.a)82.21b)136.23c)164.42d)674.24Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the safe stopping sight distance for a design speed of 60 km/h for two-way traffic on a single lane road. The reaction time of driver is 2.5 sec.a)82.21b)136.23c)164.42d)674.24Correct answer is option 'C'. Can you explain this answer?.
Calculate the safe stopping sight distance for a design speed of 60 km/h for two-way traffic on a single lane road. The reaction time of driver is 2.5 sec.a)82.21b)136.23c)164.42d)674.24Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Calculate the safe stopping sight distance for a design speed of 60 km/h for two-way traffic on a single lane road. The reaction time of driver is 2.5 sec.a)82.21b)136.23c)164.42d)674.24Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the safe stopping sight distance for a design speed of 60 km/h for two-way traffic on a single lane road. The reaction time of driver is 2.5 sec.a)82.21b)136.23c)164.42d)674.24Correct answer is option 'C'. Can you explain this answer?.
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