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The average gate power dissipation for an SCR is 0.5 Watts the voltage applied to the gate is Vg = 10 V. What is the maximum value of current Ig for safe operation?
  • a)
    0.25 A
  • b)
    10 A
  • c)
    0.05 A
  • d)
    0.1 A
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The average gate power dissipation for an SCR is 0.5 Watts the voltage...
Vg.Ig = 0.5 W, the power dissipation mustn’t exceed the average power dissipation.
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Most Upvoted Answer
The average gate power dissipation for an SCR is 0.5 Watts the voltage...
Solution:
Given:
Average gate power dissipation (Pavg) = 0.5 Watts
Voltage applied to the gate (Vg) = 10 V

To find:
Maximum value of current (Ig) for safe operation

Formula:
Power dissipation (P) = Voltage (V) * Current (I)
Pavg = Vavg * Iavg

Explanation:
The average power dissipation of the SCR gate can be calculated using the formula Pavg = Vavg * Iavg, where Vavg is the average voltage applied to the gate and Iavg is the average current flowing through the gate.

From the given information, Pavg = 0.5 Watts and Vavg = 10 V. We need to find the maximum value of Ig for safe operation.

To find Iavg, rearrange the formula:
Iavg = Pavg / Vavg

Substitute the given values:
Iavg = 0.5 Watts / 10 V
Iavg = 0.05 Amps

Since the SCR is a current-controlled device, the average current (Iavg) is the same as the maximum current (Imax) for safe operation. Therefore, the maximum value of current Ig for safe operation is 0.05 Amps.

Therefore, the correct answer is option C) 0.05 A.
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The average gate power dissipation for an SCR is 0.5 Watts the voltage applied to the gate is Vg = 10 V. What is the maximum value of current Ig for safe operation?a)0.25 Ab)10 Ac)0.05 Ad)0.1 ACorrect answer is option 'C'. Can you explain this answer?
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