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CH3NH2 (0.1 mole, Kb = 5 × 10-4) is added to 0.08 moles of HCl and the solution is diluted to one litre, resulting hydrogen ion concentration is      [JEE 2005]
  • a)
    1.6 × 10-11
  • b)
    8 × 10-11
  • c)
    5 × 10-5
  • d)
    2 × 10-2
Correct answer is option 'B'. Can you explain this answer?
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CH3NH2 (0.1 mole, Kb = 5 × 10-4) is added to 0.08 moles of HCl a...
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Option (b)
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CH3NH2 (0.1 mole, Kb = 5 × 10-4) is added to 0.08 moles of HCl a...
In order to find the pH of CH3NH2, we need to calculate the concentration of OH- ions in the solution.

CH3NH2 is a weak base, so it will react with water to produce CH3NH3+ (conjugate acid) and OH- ions.

The balanced chemical equation for this reaction is:

CH3NH2 + H2O -> CH3NH3+ + OH-

From the equation, we can see that the ratio of CH3NH2 to OH- is 1:1.

Given that the concentration of CH3NH2 is 0.1 mole, the concentration of OH- ions will also be 0.1 mole.

Now, we can use the equation for Kb to calculate the concentration of OH- ions:

Kb = [CH3NH3+][OH-]/[CH3NH2]

5 = (x)(0.1)/(0.1)

5 = x

Therefore, the concentration of OH- ions is 0.1 mole.

To find the pOH, we can use the equation:

pOH = -log[OH-]

pOH = -log(0.1)

pOH = 1

Finally, we can find the pH using the equation:

pH = 14 - pOH

pH = 14 - 1

pH = 13
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CH3NH2 (0.1 mole, Kb = 5 × 10-4) is added to 0.08 moles of HCl and the solution is diluted to one litre, resulting hydrogen ion concentration is [JEE 2005] a)1.6 × 10-11b)8 × 10-11c)5 × 10-5d)2 × 10-2Correct answer is option 'B'. Can you explain this answer?
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CH3NH2 (0.1 mole, Kb = 5 × 10-4) is added to 0.08 moles of HCl and the solution is diluted to one litre, resulting hydrogen ion concentration is [JEE 2005] a)1.6 × 10-11b)8 × 10-11c)5 × 10-5d)2 × 10-2Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about CH3NH2 (0.1 mole, Kb = 5 × 10-4) is added to 0.08 moles of HCl and the solution is diluted to one litre, resulting hydrogen ion concentration is [JEE 2005] a)1.6 × 10-11b)8 × 10-11c)5 × 10-5d)2 × 10-2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CH3NH2 (0.1 mole, Kb = 5 × 10-4) is added to 0.08 moles of HCl and the solution is diluted to one litre, resulting hydrogen ion concentration is [JEE 2005] a)1.6 × 10-11b)8 × 10-11c)5 × 10-5d)2 × 10-2Correct answer is option 'B'. Can you explain this answer?.
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