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A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.
Q.
What ist rue regarding D ?
- a)It forms a yellow precipitate with KOH/I2
- b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazine
- c)On oxidation with K2Cr2O7/H2SO4, it forms B
- d)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisation
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A neutral organic compound A(C10H20O2) neither reduces Tollen’s ...
From the given information, it appears that A is an ester. Since, D on Tischenko reaction gives back A indicates that in ester, both acid and alcohol fragments (B and C respectively) has five carbon atoms each. Also, C is an alcohol which has a chiral carbon and no CH3CH(OH)—grouping (not giving iodoform). Controlled oxidation of C gives D, a carbonyl which is still chiral. Hence, Dmust be an aldehyde with a chiral carbon.
Most Upvoted Answer
A neutral organic compound A(C10H20O2) neither reduces Tollen’s ...
**D Explanation:**
**Properties of Compound D:**
- **Does not form a yellow precipitate with KOH/I2**
- This property indicates that compound D does not contain a methyl ketone group.
- **Forms an orange precipitate with 2,4-dinitrophenyl hydrazine**
- This property suggests that compound D contains a carbonyl group, possibly an aldehyde or a ketone.
- **On oxidation with K2Cr2O7/H2SO4, forms B**
- This property indicates that compound D can be oxidized to form compound B, suggesting the presence of a secondary alcohol group in D.
- **On treatment with NaHSO3, forms a salt that cannot be separated by fractional crystallization**
- This property suggests that compound D contains a sulfonate group, making it difficult to separate the salt formed by treatment with NaHSO3.
Therefore, the correct statement is:
c) On oxidation with K2Cr2O7/H2SO4, it forms B
**Properties of Compound D:**
- **Does not form a yellow precipitate with KOH/I2**
- This property indicates that compound D does not contain a methyl ketone group.
- **Forms an orange precipitate with 2,4-dinitrophenyl hydrazine**
- This property suggests that compound D contains a carbonyl group, possibly an aldehyde or a ketone.
- **On oxidation with K2Cr2O7/H2SO4, forms B**
- This property indicates that compound D can be oxidized to form compound B, suggesting the presence of a secondary alcohol group in D.
- **On treatment with NaHSO3, forms a salt that cannot be separated by fractional crystallization**
- This property suggests that compound D contains a sulfonate group, making it difficult to separate the salt formed by treatment with NaHSO3.
Therefore, the correct statement is:
c) On oxidation with K2Cr2O7/H2SO4, it forms B
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A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer?
Question Description
A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer?.
A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer?.
Solutions for A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Here you can find the meaning of A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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