A neutral organic compound A(C10H20O2) neither reduces Tollens reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehlings solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer?

Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity

Open App

Class 12 Exam > Class 12 Questions > A neutral organic compound A(C10H20O2) neithe...

Join the Discussion on the App

A neutral organic compound A(C₁₀H₂₀O₂) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO₃/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C₂H₅O)₃ Al solution gives back A.

What ist rue regarding D ?

a)
It forms a yellow precipitate with KOH/I₂
b)
It forms an orange precipitate with 2, 4-dinitrophenyl hydrazine
c)
On oxidation with K₂Cr₂O₇/H₂SO₄, it forms B
d)
On treatment with NaHSO₃, it forms salt which cannot be separated by fractional crystallisation

Correct answer is option 'C'. Can you explain this answer?

FREE This question is part of

Test: Tests & Distinctions

Attempt Test

Attempt this Test

Verified Answer

A neutral organic compound A(C10H20O2) neither reduces Tollen’s ...

From the given information, it appears that A is an ester. Since, D on Tischenko reaction gives back A indicates that in ester, both acid and alcohol fragments (B and C respectively) has five carbon atoms each. Also, C is an alcohol which has a chiral carbon and no CH₃CH(OH)—grouping (not giving iodoform). Controlled oxidation of C gives D, a carbonyl which is still chiral. Hence, Dmust be an aldehyde with a chiral carbon.

View all questions of this test

Most Upvoted Answer

A neutral organic compound A(C10H20O2) neither reduces Tollen’s ...

**D Explanation:**
**Properties of Compound D:**
- **Does not form a yellow precipitate with KOH/I2**
- This property indicates that compound D does not contain a methyl ketone group.
- **Forms an orange precipitate with 2,4-dinitrophenyl hydrazine**
- This property suggests that compound D contains a carbonyl group, possibly an aldehyde or a ketone.
- **On oxidation with K2Cr2O7/H2SO4, forms B**
- This property indicates that compound D can be oxidized to form compound B, suggesting the presence of a secondary alcohol group in D.
- **On treatment with NaHSO3, forms a salt that cannot be separated by fractional crystallization**
- This property suggests that compound D contains a sulfonate group, making it difficult to separate the salt formed by treatment with NaHSO3.
Therefore, the correct statement is:
c) On oxidation with K2Cr2O7/H2SO4, it forms B

View all answers Start learning for free

< Previous Question Next Question >

Explore Courses for Class 12 exam

Similar Class 12 Doubts

A neutral organic compound A(C10H20O2) neither reduces Tollens reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehlings solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.The correct statement regarding the following reaction is

View answer

Comprehension TypeDirection (Q. Nos. 15-17) This section contains a paragraph, describing theory, experiments, data, etc.Three questions related to the paragraph have been given. Each question has only one correct answer among the four given options (

View answer

Passage IAn unknown organic compound A is determined to have molecular formula C6H12Oand passing it through chiral column does not separate it into enantiomers. A does not react with Br2 nor with cold, dilute alkaline KMnO4. Heating A with concentrated H2SO4 gives product B (C6H10) which can be separated into enantiomers. Ozonolysis of a single enantiomer of B produces C, an optically active keto-aldehyde of formula C6H10O2 which gives positive iodoform test.Q.The correct statement regarding C is

View answer

An organic compound X (C7H16O) gives effervescence with Na. X has both enantiomers and diastereomers. X gives yellow precipitate with alkaline iodine solution. With CrO3 - H2SO4 , X is converted into C7H14O(Y) which has enantiom ers but not diastereom ers. X on refluxing with H2SO4 isomerises to Z which neither gives yellow precipitate with alkaline iodine nor changes colour of CrO3 - H2SO4 . What is the minim um number of carbons that can be present in the parent chain of X ? Correct answer is '5'. Can you explain this answer?

View answer

Passage IAn unknown organic compound A is determined to have molecular formula C6H12Oand passing it through chiral column does not separate it into enantiomers. A does not react with Br2 nor with cold, dilute alkaline KMnO4. Heating A with concentrated H2SO4 gives product B (C6H10) which can be separated into enantiomers. Ozonolysis of a single enantiomer of B produces C, an optically active keto-aldehyde of formula C6H10O2 which gives positive iodoform test.Q.The correct statement regarding the outcome of the following reaction is

View answer

A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer?

Share with a Friend

Answer this doubt

Question Description
A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer?.

Solutions for A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

Here you can find the meaning of A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.What ist rue regarding D ?a)It forms a yellow precipitate with KOH/I2b)It forms an orange precipitate with 2, 4-dinitrophenyl hydrazinec)On oxidation with K2Cr2O7/H2SO4, it forms Bd)On treatment with NaHSO3, it forms salt which cannot be separated by fractional crystallisationCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.

Explore Courses for Class 12 exam