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Sn = 2Sn-1 + 4 and Qn = 4Qn-1 + 8 for all n > 1. If S5 = Q4 and S7 = 316, what is the first value of n for whichQn is an integer?
  • a)
    1
  • b)
    2
  • c)
    3
  • d)
    4
  • e)
    5
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Sn = 2Sn-1 + 4 and Qn = 4Qn-1 + 8 for all n > 1. If S5 = Q4 and S7 ...
If S7 = 316, then 316 = 2S6 + 4, which means that S6=156.
 
We can then solve for S5
156 = 2S5 + 4, so S5 = 76 
 
Since S5 = Q4, we know that Q4 = 76 and we can now solve for previous Qn’s to find the first n value for which Qn is an integer. 
 
To find Q3: 76 = 4Q3 + 8, so Q3 = 17
To find Q2:  17 = 4Q2 + 8, so Q2 = 9/2
It is clear that Q1 will also not be an integer so there is no need to continue.
 
Q3 (n = 3) is the first integer value. 
 
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