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If the relation between x and y is 5y-3x =10 and the mean deviation about mean for x is 12 ,then the mean deviation of y about mean is ?
Verified Answer
If the relation between x and y is 5y-3x =10 and the mean deviation ab...
5y-3x=10
x=12
5y-3x12=10
5y-36=10
5y=46
y=46/5
y=9.2
x=12
5y-3x12=10
5y-36=10
5y=46
y=46/5
y=9.2
This question is part of UPSC exam. View all CA Foundation courses
Most Upvoted Answer
If the relation between x and y is 5y-3x =10 and the mean deviation ab...
5y-3x=10
x=12
5y-3�12=10
5y-36=10
5y=46
y=46/5
y=9.2
x=12
5y-3�12=10
5y-36=10
5y=46
y=46/5
y=9.2
Community Answer
If the relation between x and y is 5y-3x =10 and the mean deviation ab...
Mean Deviation of y about mean
- To find the mean deviation of y about mean, we first need to isolate y in the given relation 5y - 3x = 10.
- Rearranging the equation, we get y = (3x + 10) / 5.
- Now, let's find the mean of x by using the formula for mean: Mean = Σx / n, where n is the total number of observations.
- To calculate the mean deviation of x about mean, we use the formula: Mean Deviation = Σ|xi - Mean| / n.
- Given that the mean deviation of x about mean is 12, we know that the sum of the absolute differences between each x value and the mean is 12 times the total number of observations.
- Now, substituting the value of x in terms of y into the formula for mean deviation, we can calculate the mean deviation of y about mean.
- Since the relation between x and y is linear, the mean deviation of y about mean will also be 12.
- To find the mean deviation of y about mean, we first need to isolate y in the given relation 5y - 3x = 10.
- Rearranging the equation, we get y = (3x + 10) / 5.
- Now, let's find the mean of x by using the formula for mean: Mean = Σx / n, where n is the total number of observations.
- To calculate the mean deviation of x about mean, we use the formula: Mean Deviation = Σ|xi - Mean| / n.
- Given that the mean deviation of x about mean is 12, we know that the sum of the absolute differences between each x value and the mean is 12 times the total number of observations.
- Now, substituting the value of x in terms of y into the formula for mean deviation, we can calculate the mean deviation of y about mean.
- Since the relation between x and y is linear, the mean deviation of y about mean will also be 12.
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If the relation between x and y is 5y-3x =10 and the mean deviation about mean for x is 12 ,then the mean deviation of y about mean is ?
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If the relation between x and y is 5y-3x =10 and the mean deviation about mean for x is 12 ,then the mean deviation of y about mean is ? for CA Foundation 2025 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If the relation between x and y is 5y-3x =10 and the mean deviation about mean for x is 12 ,then the mean deviation of y about mean is ? covers all topics & solutions for CA Foundation 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the relation between x and y is 5y-3x =10 and the mean deviation about mean for x is 12 ,then the mean deviation of y about mean is ?.
If the relation between x and y is 5y-3x =10 and the mean deviation about mean for x is 12 ,then the mean deviation of y about mean is ? for CA Foundation 2025 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If the relation between x and y is 5y-3x =10 and the mean deviation about mean for x is 12 ,then the mean deviation of y about mean is ? covers all topics & solutions for CA Foundation 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the relation between x and y is 5y-3x =10 and the mean deviation about mean for x is 12 ,then the mean deviation of y about mean is ?.
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