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Decomposition of benzene diozonium chloride by using Cu2Cl2/HCl to form chlorobenzene is
  • a)
    Sandmeyer's reaction
  • b)
    Friedel – Crafts reaction
  • c)
    Finkelstein reaction
  • d)
    Wurtz – Fittig reaction
Correct answer is option 'A'. Can you explain this answer?
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Sandmeyer's Reaction

Sandmeyer's reaction is a chemical reaction used to convert an aromatic diazonium salt into a new functional group. In this reaction, the diazonium salt is decomposed and replaced with a new functional group.

Decomposition of Benzene Diazonium Chloride

In the given question, the benzene diazonium chloride is decomposed using Cu2Cl2/HCl to form chlorobenzene. Let's understand the reaction step by step:

1. Formation of Benzene Diazonium Chloride:
- The diazonium ion (N2+) is formed by the reaction of an amine with nitrous acid (HNO2).
- In this case, benzene reacts with nitrous acid to form benzene diazonium chloride (C6H5N2Cl).

2. Decomposition of Benzene Diazonium Chloride:
- Benzene diazonium chloride is a highly reactive compound and can easily decompose.
- In the presence of a copper(I) chloride catalyst (Cu2Cl2) and hydrochloric acid (HCl), the diazonium salt decomposes to form chlorobenzene.
- The reaction proceeds as follows:
C6H5N2Cl + Cu2Cl2/HCl → C6H5Cl + N2 + CuCl2

Explanation of the Reaction

1. Copper(I) Chloride Catalyst (Cu2Cl2):
- Copper(I) chloride (Cu2Cl2) acts as a catalyst in this reaction.
- It helps in the decomposition of the diazonium salt and promotes the formation of the desired product.

2. Hydrochloric Acid (HCl):
- Hydrochloric acid (HCl) provides the necessary acidic conditions for the reaction.
- It helps in the protonation of the diazonium ion, making it more reactive and prone to decomposition.

3. Formation of Chlorobenzene:
- In the reaction, the diazonium chloride is decomposed, resulting in the formation of chlorobenzene (C6H5Cl).
- The nitrogen gas (N2) and copper(II) chloride (CuCl2) are also produced as byproducts of the reaction.

Conclusion

The decomposition of benzene diazonium chloride using Cu2Cl2/HCl to form chlorobenzene is an example of Sandmeyer's reaction. This reaction is commonly used to replace the diazonium group with a new functional group, in this case, the chlorine atom. The presence of a copper(I) chloride catalyst and hydrochloric acid helps in the decomposition and formation of the desired product.
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Decomposition of benzene diozonium chloride by using Cu2Cl2/HCl to form chlorobenzene isa)Sandmeyer's reactionb)Friedel – Crafts reactionc)Finkelstein reactiond)Wurtz – Fittig reactionCorrect answer is option 'A'. Can you explain this answer?
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Decomposition of benzene diozonium chloride by using Cu2Cl2/HCl to form chlorobenzene isa)Sandmeyer's reactionb)Friedel – Crafts reactionc)Finkelstein reactiond)Wurtz – Fittig reactionCorrect answer is option 'A'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Decomposition of benzene diozonium chloride by using Cu2Cl2/HCl to form chlorobenzene isa)Sandmeyer's reactionb)Friedel – Crafts reactionc)Finkelstein reactiond)Wurtz – Fittig reactionCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Decomposition of benzene diozonium chloride by using Cu2Cl2/HCl to form chlorobenzene isa)Sandmeyer's reactionb)Friedel – Crafts reactionc)Finkelstein reactiond)Wurtz – Fittig reactionCorrect answer is option 'A'. Can you explain this answer?.
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