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70, 75,80,85,90,105,105,130,130,130
The list shown consists of the times, in seconds, that i took each of 10 schoolchildren to run a distance of 400 on of meters. If the standard devastation of the 10 running times is 22.4 seconds, rounded to the nearest tenth of a second, how many of the 10 running times are more than 1 standard deviation below the mean of the 10 running times?
  • a)
    one
  • b)
    two
  • c)
    three
  • d)
    four
  • e)
    five
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
70, 75,80,85,90,105,105,130,130,130The list shown consists of the time...
Average=100
1 standard deviation below the mean: less than 100-22.4=77.6
Obviously, 70 and 75 can fulfill the requirements.
Answer is B
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70, 75,80,85,90,105,105,130,130,130The list shown consists of the time...
Given data:
List of running times = 70, 75,80,85,90,105,105,130,130,130
Standard deviation = 22.4

Mean of the running times:
Mean = (70+75+80+85+90+105+105+130+130+130)/10
Mean = 97 seconds

One standard deviation below the mean:
One standard deviation below the mean = Mean - Standard deviation
One standard deviation below the mean = 97 - 22.4
One standard deviation below the mean = 74.6 seconds

Number of running times more than one standard deviation below the mean:
To find the number of running times more than one standard deviation below the mean, we need to count the number of running times that are less than 74.6 seconds.

The running times that are less than 74.6 seconds are:
70, 75, 80, and 85

Therefore, the number of running times more than one standard deviation below the mean is two.

Answer: Option B (two)
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70, 75,80,85,90,105,105,130,130,130The list shown consists of the times, in seconds, that i took each of 10 schoolchildren to run a distance of 400 on of meters. If the standard devastation of the 10 running times is 22.4 seconds, rounded to the nearest tenth of a second, how many of the 10 running times are more than 1 standard deviation below the mean of the 10 running times?a)oneb)twoc)threed)foure)fiveCorrect answer is option 'B'. Can you explain this answer?
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