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For the set of terms [x, y, x + y, x – 4y, xy, 2y], if y > 6 and the mean of the set equals y + 3, then
the median must be
  • a)
    (x + y) / 2
  • b)
    y+3
  • c)
    y
  • d)
    3y/2
  • e)
    (x/2) + y
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
For the set of terms [x, y, x + y, x – 4y, xy, 2y], if y > 6 ...
The mean of a set is equal to the sum of terms divided by the number of terms in the set. Therefore,


x = 6. Given that y > 6 and substituting x = 6, the terms of the set can now be ordered from least to greatest: 
6 – 4y, 6, y, y + 6, 2y, 6y. The median of a set of six terms is the mean of the third and fourth terms (the two middle terms). The mean of the terms y and y + 6 is 

The correct answer is B.
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Most Upvoted Answer
For the set of terms [x, y, x + y, x – 4y, xy, 2y], if y > 6 ...
Y, x + y], the pattern appears to be that each term is a combination of x and y, either as a single variable or as a sum of the two variables. The terms are arranged in increasing complexity, starting with individual variables and progressing to the sum of x and y.
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For the set of terms [x, y, x + y, x – 4y, xy, 2y], if y > 6 and the mean of the set equals y + 3, thenthe median must bea)(x + y) / 2b)y+3c)yd)3y/2e)(x/2) + yCorrect answer is option 'B'. Can you explain this answer?
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