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Molecular formular C3H6Br2 can have (including stereoisomers):
- a)Two gem dibromide
- b)One vic dibromide
- c)Two tertiary dibromo alkane
- d)Two secondary dibromo alkane
Correct answer is option 'A'. Can you explain this answer?
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Molecular formular C3H6Br2can have (including stereoisomers):a)Two gem...
C3H6Br2
Two gem dibromide.
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Molecular formular C3H6Br2can have (including stereoisomers):a)Two gem...
Understanding C3H6Br2 Isomers
The molecular formula C3H6Br2 indicates that the compound contains three carbon atoms, six hydrogen atoms, and two bromine atoms. We can categorize the potential isomers based on their structure and arrangement of bromine atoms.
Types of Isomers
1. Geminal Dibromides
- Geminal dibromides have both bromine atoms attached to the same carbon atom.
- For C3H6Br2, two distinct geminal dibromides can be formed:
- 1,1-Dibromopropane (both Br on the first carbon).
- 2-Bromopropane (one Br on the second carbon while the first carbon is also occupied).
2. Vicinal Dibromides
- Vicinal dibromides have bromine atoms attached to adjacent carbon atoms.
- For C3H6Br2, only one vicinal dibromide can be formed:
- 1,2-Dibromopropane (Br on the first and second carbons).
3. Tertiary and Secondary Dibromo Alkanes
- A tertiary dibromo alkane would require a carbon with three other carbon atoms attached, which C3H6Br2 cannot satisfy.
- Similarly, C3H6Br2 cannot produce two distinct secondary dibromo alkanes due to structural limitations.
Conclusion
The correct answer is option 'A' because two distinct geminal dibromides can indeed be formed from the molecular formula C3H6Br2, while only one vicinal dibromide is possible, and no tertiary or secondary dibromo alkanes can be formed. Thus, the focus on geminal isomers confirms the selection.
The molecular formula C3H6Br2 indicates that the compound contains three carbon atoms, six hydrogen atoms, and two bromine atoms. We can categorize the potential isomers based on their structure and arrangement of bromine atoms.
Types of Isomers
1. Geminal Dibromides
- Geminal dibromides have both bromine atoms attached to the same carbon atom.
- For C3H6Br2, two distinct geminal dibromides can be formed:
- 1,1-Dibromopropane (both Br on the first carbon).
- 2-Bromopropane (one Br on the second carbon while the first carbon is also occupied).
2. Vicinal Dibromides
- Vicinal dibromides have bromine atoms attached to adjacent carbon atoms.
- For C3H6Br2, only one vicinal dibromide can be formed:
- 1,2-Dibromopropane (Br on the first and second carbons).
3. Tertiary and Secondary Dibromo Alkanes
- A tertiary dibromo alkane would require a carbon with three other carbon atoms attached, which C3H6Br2 cannot satisfy.
- Similarly, C3H6Br2 cannot produce two distinct secondary dibromo alkanes due to structural limitations.
Conclusion
The correct answer is option 'A' because two distinct geminal dibromides can indeed be formed from the molecular formula C3H6Br2, while only one vicinal dibromide is possible, and no tertiary or secondary dibromo alkanes can be formed. Thus, the focus on geminal isomers confirms the selection.
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Molecular formular C3H6Br2can have (including stereoisomers):a)Two gem dibromideb)One vic dibromidec)Two tertiary dibromo alkaned)Two secondary dibromo alkaneCorrect answer is option 'A'. Can you explain this answer?
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Molecular formular C3H6Br2can have (including stereoisomers):a)Two gem dibromideb)One vic dibromidec)Two tertiary dibromo alkaned)Two secondary dibromo alkaneCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Molecular formular C3H6Br2can have (including stereoisomers):a)Two gem dibromideb)One vic dibromidec)Two tertiary dibromo alkaned)Two secondary dibromo alkaneCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Molecular formular C3H6Br2can have (including stereoisomers):a)Two gem dibromideb)One vic dibromidec)Two tertiary dibromo alkaned)Two secondary dibromo alkaneCorrect answer is option 'A'. Can you explain this answer?.
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