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A car, moving with a speed of 50 km/hr, can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/hr, the minimum stopping distance is
- a)12 m
- b)18 m
- c)24 m
- d)6 m
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A car, moving with a speed of 50 km/hr, can be stopped by brakes after...
Dividing (i) and (ii) we get
Most Upvoted Answer
A car, moving with a speed of 50 km/hr, can be stopped by brakes after...
We know that retardation of a car with an initial speed of 50kmph stops after 6 m.
We know that v2 - u2 = 2as (third equation of motion)
0 - 50^2 = 2 * a * 6
a = - 50^2 / 12
Hence when the initial speed is 100 kmph
We get,
-100^2 = 2 * a * s
2 * s = 12 * (100^2 / 50^2) = 48m
s=24m
Thus we get s = 24 m.
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Community Answer
A car, moving with a speed of 50 km/hr, can be stopped by brakes after...
Given:
- Initial speed of the car, v1 = 50 km/hr
- Stopping distance at this speed, d1 = 6 m
- New speed of the car, v2 = 100 km/hr
To find:
- Minimum stopping distance at the new speed
Formula:
The stopping distance of a car depends on its initial speed, final speed, and the coefficient of friction between the tires and the road. The equation that relates these variables is:
(d2/d1) = (v2^2/v1^2)
where d2 is the stopping distance at the new speed v2.
Calculation:
Given the initial speed, v1 = 50 km/hr and the stopping distance at this speed, d1 = 6 m.
We need to find the minimum stopping distance at the new speed, v2 = 100 km/hr.
Using the formula mentioned above, we can write:
(d2/6) = (100^2/50^2)
Simplifying the equation:
d2 = 6 * (100^2/50^2)
d2 = 6 * (10000/2500)
d2 = 6 * 4
d2 = 24 m
Therefore, the minimum stopping distance at a speed of 100 km/hr is 24 m.
Answer:
The correct answer is option C) 24 m.
- Initial speed of the car, v1 = 50 km/hr
- Stopping distance at this speed, d1 = 6 m
- New speed of the car, v2 = 100 km/hr
To find:
- Minimum stopping distance at the new speed
Formula:
The stopping distance of a car depends on its initial speed, final speed, and the coefficient of friction between the tires and the road. The equation that relates these variables is:
(d2/d1) = (v2^2/v1^2)
where d2 is the stopping distance at the new speed v2.
Calculation:
Given the initial speed, v1 = 50 km/hr and the stopping distance at this speed, d1 = 6 m.
We need to find the minimum stopping distance at the new speed, v2 = 100 km/hr.
Using the formula mentioned above, we can write:
(d2/6) = (100^2/50^2)
Simplifying the equation:
d2 = 6 * (100^2/50^2)
d2 = 6 * (10000/2500)
d2 = 6 * 4
d2 = 24 m
Therefore, the minimum stopping distance at a speed of 100 km/hr is 24 m.
Answer:
The correct answer is option C) 24 m.
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A car, moving with a speed of 50 km/hr, can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/hr, the minimum stopping distance isa)12 mb)18 mc)24 md)6 mCorrect answer is option 'C'. Can you explain this answer?
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