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A block of mass 0.1 is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is :
- a)2.5 N
- b)0.98 N
- c)4.9 N
- d)0.49 N
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A block of mass 0.1 is held against a wall applying a horizontal force...
Limiting frictional force, fl = µsN = 0.5 × 5 = 2.5 N. But force tending to produce relative motion is the weight (W) of the block which is less than fl. Therefore, the frictional force is equal to the weight, the magnitude of the frictional force f has to balance the weight 0.98 N acting downwards.
Therefore the frictional force = 0.98 N.
Most Upvoted Answer
A block of mass 0.1 is held against a wall applying a horizontal force...
To find the magnitude of the frictional force acting on the block, we can use the equation for friction:
Frictional force = coefficient of friction * normal force
1. Calculate the normal force:
The normal force is the force exerted by the wall on the block perpendicular to the surface of contact. Since the block is held against the wall, the normal force is equal in magnitude and opposite in direction to the force applied on the block.
Normal force = force applied on the block = 5 N
2. Calculate the frictional force:
The frictional force is given by the equation:
Frictional force = coefficient of friction * normal force
Substituting the given values:
Frictional force = 0.5 * 5 N
Frictional force = 2.5 N
Therefore, the magnitude of the frictional force acting on the block is 2.5 N.
Frictional force = coefficient of friction * normal force
1. Calculate the normal force:
The normal force is the force exerted by the wall on the block perpendicular to the surface of contact. Since the block is held against the wall, the normal force is equal in magnitude and opposite in direction to the force applied on the block.
Normal force = force applied on the block = 5 N
2. Calculate the frictional force:
The frictional force is given by the equation:
Frictional force = coefficient of friction * normal force
Substituting the given values:
Frictional force = 0.5 * 5 N
Frictional force = 2.5 N
Therefore, the magnitude of the frictional force acting on the block is 2.5 N.
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A block of mass 0.1 is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is :a)2.5 Nb)0.98 Nc)4.9 Nd)0.49 NCorrect answer is option 'B'. Can you explain this answer?
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A block of mass 0.1 is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is :a)2.5 Nb)0.98 Nc)4.9 Nd)0.49 NCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A block of mass 0.1 is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is :a)2.5 Nb)0.98 Nc)4.9 Nd)0.49 NCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 0.1 is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is :a)2.5 Nb)0.98 Nc)4.9 Nd)0.49 NCorrect answer is option 'B'. Can you explain this answer?.
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