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A block of mass 0.1 Kg is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is 
  • a)
    0.49 N 
  • b)
    0.98 N 
  • c)
    4.9N
  • d)
    2.5 N
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A block of mass 0.1 Kg is held against a wall applying a horizontal fo...
Solution:

Given,

Mass of the block, m = 0.1 kg

Applied force, F = 5 N

Coefficient of friction, μ = 0.5

We need to find the magnitude of the frictional force acting on the block.

To find the frictional force, we need to use the formula:

Frictional force, f = μN

where N is the normal force acting on the block.

Calculating the Normal Force:

The normal force acting on the block is equal and opposite to the force applied on the block towards the wall.

So,

N = F = 5 N

Calculating the Frictional Force:

Substituting the values of μ and N in the formula for frictional force, we get:

f = μN = 0.5 × 5 N = 2.5 N

Therefore, the magnitude of the frictional force acting on the block is 2.5 N.

Hence, the correct answer is option B.
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A block of mass 0.1 Kg is held against a wall applying a horizontal fo...
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A block of mass 0.1 Kg is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block isa)0.49 Nb)0.98 Nc)4.9Nd)2.5 NCorrect answer is option 'B'. Can you explain this answer?
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A block of mass 0.1 Kg is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block isa)0.49 Nb)0.98 Nc)4.9Nd)2.5 NCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A block of mass 0.1 Kg is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block isa)0.49 Nb)0.98 Nc)4.9Nd)2.5 NCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 0.1 Kg is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block isa)0.49 Nb)0.98 Nc)4.9Nd)2.5 NCorrect answer is option 'B'. Can you explain this answer?.
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