A block of mass 0.1 is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is :

- a)9.8 N
- b)
- c)
- d)0.49 N

Correct answer is option 'A'. Can you explain this answer?

3 Answers

Sonali Kawetra
answered
Aug 25, 2019

The force acting on the block along the incline to shift the block downwards

= mg sin θ = 2 × 9.8 sin 30° = 9.8 N

The limiting frictional force

Note : The frictional force is never greater than the force tending to produce relative motion.

Therefore the frictional force is 9.8 N

Therefore the frictional force is 9.8 N

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A block of mass 0.1 is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is :a)9.8 Nb)c)d)0.49 NCorrect answer is option 'A'. Can you explain this answer? over here on EduRev! Apart from being the largest JEE community, EduRev has the largest solved
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