A block of mass 0.1 is held against a wall applying a horizontal force of 5 N on the block. If the  coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is :
  • a)
    9.8 N
  • b)
  • c)
  • d)
    0.49 N
Correct answer is option 'A'. Can you explain this answer?

JEE Question

By Muskan Agrawal · 4 weeks ago ·JEE
3 Answers
Tanvi answered 4 weeks ago

Sonali Kawetra answered Aug 25, 2019
The force acting on the block along the incline to shift the block downwards
= mg sin θ = 2 × 9.8 sin 30° = 9.8 N
The limiting frictional force
Note : The frictional force is never greater than the force tending to produce relative motion.
Therefore the frictional force is 9.8 N

Harsh Singhal answered 4 weeks ago
I think so ans.should be d

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