Problem:
The sum of three consecutive multiples of 11 is 363. Find these multiples.

Solution:

To find the three consecutive multiples of 11, we need to follow these steps:

Step 1: Define the variables:
Let's assume the first multiple of 11 as 'x'. The next two consecutive multiples will be 'x + 11' and 'x + 22'.

Step 2: Write the equation:
The sum of these three multiples is given as 363. So we can write the equation as:
x + (x + 11) + (x + 22) = 363.

Step 3: Simplify the equation:
By combining like terms, we can simplify the equation:
3x + 33 = 363.

Step 4: Solve for x:
To solve for x, we need to isolate it on one side of the equation. We can do this by subtracting 33 from both sides:
3x = 363 - 33,
3x = 330.

Now, divide both sides of the equation by 3 to solve for x:
x = 330 / 3,
x = 110.

Step 5: Find the multiples:
Now that we have the value of x, we can substitute it back into our assumption to find the three consecutive multiples:
First multiple = x = 110.
Second multiple = x + 11 = 110 + 11 = 121.
Third multiple = x + 22 = 110 + 22 = 132.

Answer:
The three consecutive multiples of 11 that sum up to 363 are 110, 121, and 132.

110,121,132