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A solution contains HCl, Cl2HC COOH & CH3COOH at concentation 0.09 M in HCl, 0.09 M in Cl2HC COOH & 0.1 M in CH3COOH. pH for the solution is 1. Ionization constant of CH3COOH = 105. What is the magnitude of K for dichloroacetic acid ?
  • a)
    Ka = 1.25 × 10-2 
  • b)
    Ka = 2.25 × 10-2 
  • c)
    Ka = 3.75 × 10-4 
  • d)
    Ka = 5.75 × 10-2
Correct answer is option 'A'. Can you explain this answer?
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A solution contains HCl, Cl2HC COOH & CH3COOH at concentation 0.09...


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A solution contains HCl, Cl2HC COOH & CH3COOH at concentation 0.09...
To find the magnitude of K for dichloroacetic acid (Cl2HC COOH), we need to use the given information about the concentrations and the pH of the solution.

First, let's write the balanced equation for the dissociation of dichloroacetic acid:

Cl2HC COOH ⇌ Cl2HC COO- + H+

The concentration of Cl2HC COOH in the solution is given as 0.09 M, and the pH of the solution is 1. We know that pH is calculated using the equation:

pH = -log[H+]

Since the pH is 1, the concentration of H+ can be calculated using the equation:

[H+] = 10^(-pH) = 10^(-1) = 0.1 M

Now, let's consider the dissociation of dichloroacetic acid. At equilibrium, the concentration of Cl2HC COOH is (0.09 - x) M, the concentration of Cl2HC COO- is x M, and the concentration of H+ is also x M. Since Cl2HC COOH is a weak acid, we can assume that x is much smaller than 0.09 M.

Using the ionization constant (Ka) of acetic acid (CH3COOH) given as 10^(-5), we can write the expression for Ka in terms of the concentrations:

Ka = [Cl2HC COO-][H+]/[Cl2HC COOH]

Since the concentration of H+ is x and the concentration of Cl2HC COO- is also x, we can rewrite the equation as:

Ka = x^2/(0.09 - x)

Now, let's substitute the concentration of H+ calculated earlier (0.1 M) into the equation:

Ka = (0.1)^2/(0.09 - 0.1) = 0.01/(-0.01) = -1

Since the magnitude of Ka cannot be negative, we need to take the absolute value:

|Ka| = 1

Therefore, the magnitude of K for dichloroacetic acid is 1.

The correct answer is option 'A' (Ka = 1.25 x 10^(-2)).
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A solution contains HCl, Cl2HC COOH & CH3COOH at concentation 0.09 M in HCl, 0.09 M in Cl2HC COOH & 0.1 M in CH3COOH. pH for the solution is 1. Ionization constant of CH3COOH = 105. What is the magnitude of K for dichloroacetic acid ?a)Ka= 1.25 × 10-2b)Ka= 2.25 × 10-2c)Ka= 3.75 × 10-4d)Ka= 5.75 × 10-2Correct answer is option 'A'. Can you explain this answer?
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A solution contains HCl, Cl2HC COOH & CH3COOH at concentation 0.09 M in HCl, 0.09 M in Cl2HC COOH & 0.1 M in CH3COOH. pH for the solution is 1. Ionization constant of CH3COOH = 105. What is the magnitude of K for dichloroacetic acid ?a)Ka= 1.25 × 10-2b)Ka= 2.25 × 10-2c)Ka= 3.75 × 10-4d)Ka= 5.75 × 10-2Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A solution contains HCl, Cl2HC COOH & CH3COOH at concentation 0.09 M in HCl, 0.09 M in Cl2HC COOH & 0.1 M in CH3COOH. pH for the solution is 1. Ionization constant of CH3COOH = 105. What is the magnitude of K for dichloroacetic acid ?a)Ka= 1.25 × 10-2b)Ka= 2.25 × 10-2c)Ka= 3.75 × 10-4d)Ka= 5.75 × 10-2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution contains HCl, Cl2HC COOH & CH3COOH at concentation 0.09 M in HCl, 0.09 M in Cl2HC COOH & 0.1 M in CH3COOH. pH for the solution is 1. Ionization constant of CH3COOH = 105. What is the magnitude of K for dichloroacetic acid ?a)Ka= 1.25 × 10-2b)Ka= 2.25 × 10-2c)Ka= 3.75 × 10-4d)Ka= 5.75 × 10-2Correct answer is option 'A'. Can you explain this answer?.
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