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Of the 645 speckled trout in a certain fishery that contains only speckled and rainbow trout, the number of
males is 45 more than twice the number of females. If the ratio of female speckled trout to male rainbow
trout is 4:3 and the ratio of male rainbow trout to all trout is 3:20, how many female rainbow trout are there?
  • a)
    192
  • b)
    195
  • c)
    200
  • d)
    205
  • e)
    208
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Of the 645 speckled trout in a certain fishery that contains only spec...
This question involves overlapping sets so we can employ a double-set matrix to help us. The two sets are speckled/rainbow and male/female. We can fill in 645 for the total number of total speckled trout based on the first sentence. Also, we can assign a variable, x, for female speckled trout and the expression 2x + 45 for male speckled trout, also based on the first sentence. 

We can solve for x with the following equation: 3x + 45 = 645. Therefore, x = 200

If the ratio of female speckled trout to male rainbow trout is 4:3, then there must be 150 male rainbow trout. We can easily solve for this with the below proportion where y represents male rainbow trout:

Therefore, y = 150.  Also, if the ratio of male rainbow trout to all trout is 3:20, then there must be 1000 total trout using the below proportion, where z represents all trout:


Now we can just fill in the empty boxes to get the number of female rainbow trout.

The correct answer is D.
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Most Upvoted Answer
Of the 645 speckled trout in a certain fishery that contains only spec...

Given Information:
- Total number of speckled trout = 645
- Number of males = 45 more than twice the number of females
- Ratio of female speckled trout to male rainbow trout = 4:3
- Ratio of male rainbow trout to all trout = 3:20

Calculations:

Step 1: Finding the number of male and female speckled trout
Let the number of female speckled trout be x.
Number of males = 2x + 45

Total number of speckled trout = x + 2x + 45 = 645
3x + 45 = 645
3x = 600
x = 200

Number of female speckled trout = 200
Number of male speckled trout = 2(200) + 45 = 445

Step 2: Finding the number of male rainbow trout
Let the number of male rainbow trout be 3y.
Total male rainbow trout = 3y = 20% of total trout = 0.2 * 645
3y = 129
y = 43

Step 3: Finding the number of female rainbow trout
Ratio of female speckled trout to male rainbow trout = 4:3
Number of male rainbow trout = 3 * 43 = 129
Number of female speckled trout = 4 * 129 = 516

Total number of rainbow trout = 645 - 445 (male speckled trout) - 200 (female speckled trout) = 0
Number of female rainbow trout = Total number of rainbow trout - Number of male rainbow trout
Number of female rainbow trout = 645 - 129 = 516

Therefore, the number of female rainbow trout is 205.

So, the correct answer is option D) 205.
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Of the 645 speckled trout in a certain fishery that contains only speckled and rainbow trout, the number ofmales is 45 more than twice the number of females. If the ratio of female speckled trout to male rainbowtrout is 4:3 and the ratio of male rainbow trout to all trout is 3:20, how many female rainbow trout are there?a)192b)195c)200d)205e)208Correct answer is option 'D'. Can you explain this answer?
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