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Let f (x) = x3−6x2+9x+8, then f (x) is decreasing in
  • a)
    (−∞,1) ∪ (3,∞)
  • b)
    [1, 3]
  • c)
    [3,∞]
  • d)
    (−∞,1)
Correct answer is option 'B'. Can you explain this answer?
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Let f (x) =x3−6x2+9x+8, then f (x) is decreasing ina)(−...
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Let f (x) =x3−6x2+9x+8, then f (x) is decreasing ina)(−...
Understanding the Function f(x)
The function given is f(x) = x^3 - 6x^2 + 9x + 8. To determine where this function is decreasing, we need to analyze its first derivative.
Finding the First Derivative
- The first derivative f'(x) helps identify increasing and decreasing intervals.
- f'(x) = 3x^2 - 12x + 9.
Finding Critical Points
- Set the first derivative equal to zero to find critical points:
3x^2 - 12x + 9 = 0.
- Simplifying gives us:
x^2 - 4x + 3 = 0.
- Factoring results in:
(x - 1)(x - 3) = 0, leading to critical points at x = 1 and x = 3.
Test Intervals
Now we need to evaluate the sign of f'(x) in the intervals defined by these critical points:
- Interval (-∞, 1): Choose x = 0.
f'(0) = 3(0)^2 - 12(0) + 9 = 9 (positive).
- Interval (1, 3): Choose x = 2.
f'(2) = 3(2)^2 - 12(2) + 9 = -3 (negative).
- Interval (3, ∞): Choose x = 4.
f'(4) = 3(4)^2 - 12(4) + 9 = 9 (positive).
Conclusion
- f'(x) > 0 in (-∞, 1) and (3, ∞) (increasing).
- f'(x) < 0="" in="" (1,="" 3)="" />
Thus, f(x) is decreasing in the interval [1, 3], which corresponds to option 'B'. 0="" in="" (1,="" 3)="" (decreasing).="" thus,="" f(x)="" is="" decreasing="" in="" the="" interval="" [1,="" 3],="" which="" corresponds="" to="" option="">
Thus, f(x) is decreasing in the interval [1, 3], which corresponds to option 'B'.>
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