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The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO3 to a
compound with the highest oxidation state of sulphur is______
(Given data : Molar mass of water = 18 g mol-1)
compound with the highest oxidation state of sulphur is______
(Given data : Molar mass of water = 18 g mol-1)
Correct answer is '288.00'. Can you explain this answer?
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Solution:
To find the amount of water produced in the oxidation of 1 mole of rhombic sulphur, we need to determine the balanced chemical equation for the reaction.
The oxidation of rhombic sulphur by conc. HNO3 can be represented by the following balanced chemical equation:
S(s) + 6HNO3(aq) → H2SO4(aq) + 6NO2(g) + 2H2O(l)
From the balanced equation, we can see that for every 1 mole of rhombic sulphur oxidized, 2 moles of water are produced.
Calculation:
Given that the molar mass of water (H2O) is 18 g/mol, we can calculate the amount of water produced using the following steps:
1. Determine the molar mass of rhombic sulphur (S):
The molar mass of sulfur is 32 g/mol.
2. Determine the number of moles of rhombic sulphur:
Since we are given 1 mole of rhombic sulphur, the number of moles of rhombic sulphur is 1.
3. Determine the number of moles of water produced:
From the balanced equation, we know that for every 1 mole of rhombic sulphur oxidized, 2 moles of water are produced. Therefore, the number of moles of water produced is 2.
4. Determine the amount of water produced in grams:
The amount of water produced can be calculated using the formula:
Amount of water (g) = Number of moles of water × Molar mass of water
= 2 mol × 18 g/mol
= 36 g
Therefore, the amount of water produced in the oxidation of 1 mole of rhombic sulphur is 36 g.
However, the correct answer provided is '288.00'. This suggests that there may be an error in the given answer or in the question itself.
To find the amount of water produced in the oxidation of 1 mole of rhombic sulphur, we need to determine the balanced chemical equation for the reaction.
The oxidation of rhombic sulphur by conc. HNO3 can be represented by the following balanced chemical equation:
S(s) + 6HNO3(aq) → H2SO4(aq) + 6NO2(g) + 2H2O(l)
From the balanced equation, we can see that for every 1 mole of rhombic sulphur oxidized, 2 moles of water are produced.
Calculation:
Given that the molar mass of water (H2O) is 18 g/mol, we can calculate the amount of water produced using the following steps:
1. Determine the molar mass of rhombic sulphur (S):
The molar mass of sulfur is 32 g/mol.
2. Determine the number of moles of rhombic sulphur:
Since we are given 1 mole of rhombic sulphur, the number of moles of rhombic sulphur is 1.
3. Determine the number of moles of water produced:
From the balanced equation, we know that for every 1 mole of rhombic sulphur oxidized, 2 moles of water are produced. Therefore, the number of moles of water produced is 2.
4. Determine the amount of water produced in grams:
The amount of water produced can be calculated using the formula:
Amount of water (g) = Number of moles of water × Molar mass of water
= 2 mol × 18 g/mol
= 36 g
Therefore, the amount of water produced in the oxidation of 1 mole of rhombic sulphur is 36 g.
However, the correct answer provided is '288.00'. This suggests that there may be an error in the given answer or in the question itself.
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The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO3 to acompound with the highest oxidation state of sulphur is______(Given data : Molar mass of water = 18 g mol-1)Correct answer is '288.00'. Can you explain this answer?
Question Description
The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO3 to acompound with the highest oxidation state of sulphur is______(Given data : Molar mass of water = 18 g mol-1)Correct answer is '288.00'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO3 to acompound with the highest oxidation state of sulphur is______(Given data : Molar mass of water = 18 g mol-1)Correct answer is '288.00'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO3 to acompound with the highest oxidation state of sulphur is______(Given data : Molar mass of water = 18 g mol-1)Correct answer is '288.00'. Can you explain this answer?.
The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO3 to acompound with the highest oxidation state of sulphur is______(Given data : Molar mass of water = 18 g mol-1)Correct answer is '288.00'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO3 to acompound with the highest oxidation state of sulphur is______(Given data : Molar mass of water = 18 g mol-1)Correct answer is '288.00'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO3 to acompound with the highest oxidation state of sulphur is______(Given data : Molar mass of water = 18 g mol-1)Correct answer is '288.00'. Can you explain this answer?.
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The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO3 to acompound with the highest oxidation state of sulphur is______(Given data : Molar mass of water = 18 g mol-1)Correct answer is '288.00'. Can you explain this answer?, a detailed solution for The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO3 to acompound with the highest oxidation state of sulphur is______(Given data : Molar mass of water = 18 g mol-1)Correct answer is '288.00'. Can you explain this answer? has been provided alongside types of The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO3 to acompound with the highest oxidation state of sulphur is______(Given data : Molar mass of water = 18 g mol-1)Correct answer is '288.00'. Can you explain this answer? theory, EduRev gives you an
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