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The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc.HNO3 to a compound with the highest oxidation state of sulphur is __
(Given data : Molar mass of water = 18 g mol–1)
(Given data : Molar mass of water = 18 g mol–1)
Correct answer is '288.00'. Can you explain this answer?
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The amount of water produced (in g) in the oxidation of 1 mole of rhom...
S8 + 48 HNO3 → 8H2SO4 + 48NO2 + 16H2O
1 mole of rhombic sulphur produce 16 mole of H2O i.e. 288 gm of H2O
1 mole of rhombic sulphur produce 16 mole of H2O i.e. 288 gm of H2O
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The amount of water produced (in g) in the oxidation of 1 mole of rhom...
To determine the amount of water produced in the oxidation of 1 mole of rhombic sulfur (S8) by conc.HNO3 to a compound with the highest oxidation state of sulfur, we need to write the balanced chemical equation for the reaction.
The reaction can be represented as follows:
S8 + 24HNO3 -> 8H2SO4 + 24NO2 + H2O
From the balanced equation, we can see that for every mole of rhombic sulfur (S8), 1 mole of water (H2O) is produced. Therefore, the amount of water produced in the oxidation of 1 mole of rhombic sulfur is 1 mole.
Since the molar mass of water (H2O) is given as 18 g/mol, we can conclude that the amount of water produced is 18 g.
The reaction can be represented as follows:
S8 + 24HNO3 -> 8H2SO4 + 24NO2 + H2O
From the balanced equation, we can see that for every mole of rhombic sulfur (S8), 1 mole of water (H2O) is produced. Therefore, the amount of water produced in the oxidation of 1 mole of rhombic sulfur is 1 mole.
Since the molar mass of water (H2O) is given as 18 g/mol, we can conclude that the amount of water produced is 18 g.
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The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc.HNO3 to a compound with the highest oxidation state of sulphur is __(Given data : Molar mass of water = 18 g mol–1)Correct answer is '288.00'. Can you explain this answer?
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The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc.HNO3 to a compound with the highest oxidation state of sulphur is __(Given data : Molar mass of water = 18 g mol–1)Correct answer is '288.00'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc.HNO3 to a compound with the highest oxidation state of sulphur is __(Given data : Molar mass of water = 18 g mol–1)Correct answer is '288.00'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc.HNO3 to a compound with the highest oxidation state of sulphur is __(Given data : Molar mass of water = 18 g mol–1)Correct answer is '288.00'. Can you explain this answer?.
The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc.HNO3 to a compound with the highest oxidation state of sulphur is __(Given data : Molar mass of water = 18 g mol–1)Correct answer is '288.00'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc.HNO3 to a compound with the highest oxidation state of sulphur is __(Given data : Molar mass of water = 18 g mol–1)Correct answer is '288.00'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc.HNO3 to a compound with the highest oxidation state of sulphur is __(Given data : Molar mass of water = 18 g mol–1)Correct answer is '288.00'. Can you explain this answer?.
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