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A tank containing water upto a depth of 500 mm is moving vertically upward with a constant acceleration of 2.45 m/s2. Find the force exerted by fluid of specific gravity .65 on the side of tank,width of tank is 1m.
- a)996.1 N
- b)1992.2 N
- c)498.06 N
- d)124.5 N
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A tank containing water upto a depth of 500 mm is moving vertically up...
Explanation: p=ρ*g*h*(1+a/g)
=650*9.81*0.5*(1+2.45/9.81)
=3984.5 N/m2
F=wAĥ
= 650*9.81*0.5*0.5*3984.5
= 996.1N.
=650*9.81*0.5*(1+2.45/9.81)
=3984.5 N/m2
F=wAĥ
= 650*9.81*0.5*0.5*3984.5
= 996.1N.
Most Upvoted Answer
A tank containing water upto a depth of 500 mm is moving vertically up...
Given data:
- Depth of water in the tank (h) = 500 mm = 0.5 m
- Acceleration of the tank (a) = 2.45 m/s^2
- Specific gravity of fluid (SG) = 0.65
- Width of the tank (b) = 1 m
Step 1: Calculate the weight of the fluid
The weight of the fluid can be calculated using the formula:
\[ W = \gamma \times V \times g \]
where:
- \( \gamma \) = specific weight of fluid = SG x density of water x g = SG x 1000 kg/m^3 x 9.81 m/s^2
- V = volume of fluid = area x depth = b x h
- g = acceleration due to gravity = 9.81 m/s^2
Plugging in the values:
\[ W = 0.65 \times 1000 \times 9.81 \times 1 \times 0.5 = 3208.25 N \]
Step 2: Calculate the force exerted by the fluid
The force exerted by the fluid on the side of the tank can be calculated using the formula:
\[ F = W - V \times a \times \gamma \]
where:
- V = volume of fluid = b x h
- a = acceleration of the tank = 2.45 m/s^2
- \( \gamma \) = specific weight of fluid
Plugging in the values:
\[ F = 3208.25 - 1 \times 0.5 \times 2.45 \times 0.65 \times 1000 \times 9.81 = 996.1 N \]
Therefore, the force exerted by the fluid of specific gravity 0.65 on the side of the tank is 996.1 N. Hence, option A is correct.
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A tank containing water upto a depth of 500 mm is moving vertically upward with a constant acceleration of 2.45 m/s2. Find the force exerted by fluid of specific gravity .65 on the side of tank,width of tank is 1m.a)996.1 Nb)1992.2 Nc)498.06 Nd)124.5 NCorrect answer is option 'A'. Can you explain this answer?
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