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A rectangular tank is moving horizontally in the direction of its length with a constant acceleration of 4.8 m/s2. The length of tank is 7 m and depth is 1.5 m. If tank is open at the top then calculate the maximum pressure intensity at the bottom.
- a)6.3 N/cm2
- b)3.15 N/cm2
- c)12.6 N/cm2
- d)1.6 N/cm2
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A rectangular tank is moving horizontally in the direction of its leng...
Explanation: tanθ=a/g
tanθ=4.8/9.8
θ=26.07⁰
h= d+(L/2)tanθ
= 1.5+3.5tan26.07
= 3.21 m
p=ρ*g*h
=3.15 N/cm2.
tanθ=4.8/9.8
θ=26.07⁰
h= d+(L/2)tanθ
= 1.5+3.5tan26.07
= 3.21 m
p=ρ*g*h
=3.15 N/cm2.
Most Upvoted Answer
A rectangular tank is moving horizontally in the direction of its leng...
Given data:
Acceleration of the tank (a) = 4.8 m/s^2
Length of the tank (l) = 7 m
Depth of the tank (d) = 1.5 m
To find:
Maximum pressure intensity at the bottom of the tank
Formula:
Pressure (P) = ρgh
Where:
ρ = Density of the fluid
g = Acceleration due to gravity
h = Depth of the fluid
Step-by-step solution:
1. Calculate the density of the fluid:
The density of water is approximately 1000 kg/m^3.
2. Calculate the depth of the fluid:
The depth of the fluid is equal to the height of the tank, which is given as 1.5 m.
3. Calculate the acceleration due to gravity:
The acceleration due to gravity (g) is approximately 9.8 m/s^2.
4. Calculate the maximum pressure intensity at the bottom of the tank:
Using the formula P = ρgh, we can substitute the values as follows:
P = (1000 kg/m^3) * (9.8 m/s^2) * (1.5 m)
P ≈ 14,700 N/m^2
5. Convert the pressure to N/cm^2:
1 N/m^2 = 0.0001 N/cm^2
14,700 N/m^2 ≈ 1.47 N/cm^2
Therefore, the maximum pressure intensity at the bottom of the tank is approximately 1.47 N/cm^2.
Correct option: B) 3.15 N/cm^2 (rounded to two decimal places)
Note: The correct answer should be 1.47 N/cm^2, not 3.15 N/cm^2 as mentioned in the options.
Acceleration of the tank (a) = 4.8 m/s^2
Length of the tank (l) = 7 m
Depth of the tank (d) = 1.5 m
To find:
Maximum pressure intensity at the bottom of the tank
Formula:
Pressure (P) = ρgh
Where:
ρ = Density of the fluid
g = Acceleration due to gravity
h = Depth of the fluid
Step-by-step solution:
1. Calculate the density of the fluid:
The density of water is approximately 1000 kg/m^3.
2. Calculate the depth of the fluid:
The depth of the fluid is equal to the height of the tank, which is given as 1.5 m.
3. Calculate the acceleration due to gravity:
The acceleration due to gravity (g) is approximately 9.8 m/s^2.
4. Calculate the maximum pressure intensity at the bottom of the tank:
Using the formula P = ρgh, we can substitute the values as follows:
P = (1000 kg/m^3) * (9.8 m/s^2) * (1.5 m)
P ≈ 14,700 N/m^2
5. Convert the pressure to N/cm^2:
1 N/m^2 = 0.0001 N/cm^2
14,700 N/m^2 ≈ 1.47 N/cm^2
Therefore, the maximum pressure intensity at the bottom of the tank is approximately 1.47 N/cm^2.
Correct option: B) 3.15 N/cm^2 (rounded to two decimal places)
Note: The correct answer should be 1.47 N/cm^2, not 3.15 N/cm^2 as mentioned in the options.
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A rectangular tank is moving horizontally in the direction of its length with a constant acceleration of 4.8 m/s2. The length of tank is 7 m and depth is 1.5 m. If tank is open at the top then calculate the maximum pressure intensity at the bottom.a)6.3 N/cm2b)3.15 N/cm2c)12.6 N/cm2d)1.6 N/cm2Correct answer is option 'B'. Can you explain this answer?
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