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A rectangular tank is moving horizontally in the direction of its length with a constant acceleration of 5.5 m/s2. The length of tank is 5.5 m and depth is 2 m. If tank is open at the top then calculate the minimum pressure intensity at the bottom. 
  • a)
    3.8 N/cm2
  • b)
    1.9 N/cm2
  • c)
    5.7 N/cm2
  • d)
    2.6 N/cm2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A rectangular tank is moving horizontally in the direction of its leng...
Explanation: tanθ=a/g
tanθ=5.5/9.8
θ=29.28⁰
h= d-(L/2)tanθ
= 2-2.75 tan29.28
= 3.21 m
p=ρ*g*h
=1.9 N/cm2.
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Most Upvoted Answer
A rectangular tank is moving horizontally in the direction of its leng...
To find the minimum pressure intensity at the bottom of the tank, we need to consider the forces acting on the water inside the tank.

**1. Weight of the water:**
The weight of the water inside the tank creates a downward force. The weight of the water can be calculated using the formula:

Weight = density * volume * acceleration due to gravity

Since the tank is open at the top, the pressure at the top of the water column is atmospheric pressure, which we can assume to be constant. Therefore, the pressure at the bottom of the water column is greater than atmospheric pressure by an amount equal to the weight of the water.

**2. Inertial force:**
Due to the horizontal acceleration of the tank, there is an inertial force acting on the water in the opposite direction. This force can be calculated using the formula:

Inertial Force = mass * acceleration

The mass of the water can be calculated using the formula:

Mass = density * volume

**3. Net Force:**
The net force acting on the water is the difference between the weight of the water and the inertial force. This net force is responsible for creating pressure at the bottom of the tank.

**4. Pressure:**
Pressure is defined as force per unit area. To find the pressure intensity at the bottom of the tank, we need to divide the net force by the area of the bottom of the tank.

**Calculation:**
Given data:
Acceleration = 5.5 m/s^2
Length of tank = 5.5 m
Depth of tank = 2 m

**Step 1: Calculate the weight of the water:**
Density of water = 1000 kg/m^3 (assumed)
Volume of water = length * width * depth
Volume of water = 5.5 m * 1 m * 2 m = 11 m^3

Weight of water = density * volume * acceleration due to gravity
Weight of water = 1000 kg/m^3 * 11 m^3 * 9.8 m/s^2
Weight of water = 107800 N

**Step 2: Calculate the mass of the water:**
Mass = density * volume
Mass = 1000 kg/m^3 * 11 m^3
Mass = 11000 kg

**Step 3: Calculate the inertial force:**
Inertial Force = mass * acceleration
Inertial Force = 11000 kg * 5.5 m/s^2
Inertial Force = 60500 N

**Step 4: Calculate the net force:**
Net Force = Weight of water - Inertial Force
Net Force = 107800 N - 60500 N
Net Force = 47300 N

**Step 5: Calculate the pressure intensity:**
Area of the bottom of the tank = length * width
Area of the bottom of the tank = 5.5 m * 1 m
Area of the bottom of the tank = 5.5 m^2

Pressure intensity = Net Force / Area of the bottom of the tank
Pressure intensity = 47300 N / 5.5 m^2
Pressure intensity = 8600 N/m^2

Converting pressure to N/cm^2:
1 N/m^2 = 0.01 N/cm^2
8600 N/m^2 =
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A rectangular tank is moving horizontally in the direction of its length with a constant acceleration of 5.5 m/s2. The length of tank is 5.5 m and depth is 2 m. If tank is open at the top then calculate the minimum pressure intensity at the bottom.a)3.8 N/cm2b)1.9 N/cm2c)5.7 N/cm2d)2.6 N/cm2Correct answer is option 'B'. Can you explain this answer?
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