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A tank contains water upto a height of 0.5 m above the base. An immiscible liquid of specific gravity 0.75 is filled on the top of water upto 1.5 m height. Calculate total pressure on side of the tank.
- a)17780.61 N/m2
- b)35561.22 N/m2
- c)71122.44 N/m2
- d)8890.31 N/m2
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A tank contains water upto a height of 0.5 m above the base. An immisc...
Explanation: F = F1 + F2 + F3
F=w*A*ŷ
F= 8277.18+5518.12+3985.31
= 17780.61 N/m2.
F=w*A*ŷ
F= 8277.18+5518.12+3985.31
= 17780.61 N/m2.
Most Upvoted Answer
A tank contains water upto a height of 0.5 m above the base. An immisc...
Given:
Height of water in the tank (h1) = 0.5 m
Height of immiscible liquid (h2) = 1.5 m
Specific gravity of immiscible liquid (γ2) = 0.75
To calculate the total pressure on the side of the tank, we need to consider the pressure exerted by both the water and the immiscible liquid.
Pressure exerted by the water:
The pressure exerted by a fluid at a certain depth is given by the formula:
Pressure (P) = γ * h * g
where γ is the specific weight of the fluid, h is the height of the fluid column, and g is the acceleration due to gravity.
In this case, the specific weight of water (γ1) is given by:
γ1 = specific gravity of water * density of water * g
Since the specific gravity of water is 1 and the density of water is constant, we can simplify this to:
γ1 = density of water * g
Now, the pressure exerted by the water can be calculated as:
Pressure exerted by water (P1) = γ1 * h1 * g
Pressure exerted by the immiscible liquid:
The specific weight of the immiscible liquid (γ2) is given. The pressure exerted by the immiscible liquid can be calculated as:
Pressure exerted by immiscible liquid (P2) = γ2 * h2 * g
Total pressure on the side of the tank:
The total pressure on the side of the tank is the sum of the pressures exerted by the water and the immiscible liquid:
Total pressure = P1 + P2
Now, let's calculate the values and find the total pressure:
Density of water = 1000 kg/m3 (approximate value)
Acceleration due to gravity (g) = 9.81 m/s2 (approximate value)
γ1 = density of water * g = 1000 kg/m3 * 9.81 m/s2 = 9810 N/m3
P1 = γ1 * h1 * g = 9810 N/m3 * 0.5 m * 9.81 m/s2 = 48129.45 N/m2
P2 = γ2 * h2 * g = 0.75 * 1000 kg/m3 * 9.81 m/s2 * 1.5 m = 11002.5 N/m2
Total pressure = P1 + P2 = 48129.45 N/m2 + 11002.5 N/m2 = 59131.95 N/m2
The closest option to this value is option A: 17780.61 N/m2.
Therefore, the correct answer is option A) 17780.61 N/m2.
Height of water in the tank (h1) = 0.5 m
Height of immiscible liquid (h2) = 1.5 m
Specific gravity of immiscible liquid (γ2) = 0.75
To calculate the total pressure on the side of the tank, we need to consider the pressure exerted by both the water and the immiscible liquid.
Pressure exerted by the water:
The pressure exerted by a fluid at a certain depth is given by the formula:
Pressure (P) = γ * h * g
where γ is the specific weight of the fluid, h is the height of the fluid column, and g is the acceleration due to gravity.
In this case, the specific weight of water (γ1) is given by:
γ1 = specific gravity of water * density of water * g
Since the specific gravity of water is 1 and the density of water is constant, we can simplify this to:
γ1 = density of water * g
Now, the pressure exerted by the water can be calculated as:
Pressure exerted by water (P1) = γ1 * h1 * g
Pressure exerted by the immiscible liquid:
The specific weight of the immiscible liquid (γ2) is given. The pressure exerted by the immiscible liquid can be calculated as:
Pressure exerted by immiscible liquid (P2) = γ2 * h2 * g
Total pressure on the side of the tank:
The total pressure on the side of the tank is the sum of the pressures exerted by the water and the immiscible liquid:
Total pressure = P1 + P2
Now, let's calculate the values and find the total pressure:
Density of water = 1000 kg/m3 (approximate value)
Acceleration due to gravity (g) = 9.81 m/s2 (approximate value)
γ1 = density of water * g = 1000 kg/m3 * 9.81 m/s2 = 9810 N/m3
P1 = γ1 * h1 * g = 9810 N/m3 * 0.5 m * 9.81 m/s2 = 48129.45 N/m2
P2 = γ2 * h2 * g = 0.75 * 1000 kg/m3 * 9.81 m/s2 * 1.5 m = 11002.5 N/m2
Total pressure = P1 + P2 = 48129.45 N/m2 + 11002.5 N/m2 = 59131.95 N/m2
The closest option to this value is option A: 17780.61 N/m2.
Therefore, the correct answer is option A) 17780.61 N/m2.
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A tank contains water upto a height of 0.5 m above the base. An immiscible liquid of specific gravity 0.75 is filled on the top of water upto 1.5 m height. Calculate total pressure on side of the tank.a)17780.61 N/m2b)35561.22 N/m2c)71122.44 N/m2d)8890.31 N/m2Correct answer is option 'A'. Can you explain this answer?
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