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An open tank contains water upto a depth of 350 cm and above it an oil of specific gravity 0.65 for a depth of 2.5 m. Find the pressure intensity at the extreme bottom of the tank.
Correct answer is '5.026 - 5.030'. Can you explain this answer?
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An open tank contains water upto a depth of 350 cm and above it an oil...
p = (specific gravity of water* height of water + specific gravity of oil* height of oil) * 9.81
= 5.027 N/cm2.
= 5.027 N/cm2.
Most Upvoted Answer
An open tank contains water upto a depth of 350 cm and above it an oil...
Given data:
- Depth of water (h1) = 350 cm = 3.5 m
- Depth of oil (h2) = 2.5 m
- Specific gravity of oil (γo) = 0.65
Assumptions:
- The density of water (γw) is 1000 kg/m³.
- The density of oil (γo) is 0.65 * 1000 = 650 kg/m³.
Pressure at the bottom of the tank:
To find the pressure intensity at the extreme bottom of the tank, we need to consider the pressure exerted by both the water and the oil.
Pressure due to water:
The pressure exerted by a fluid at a certain depth is given by the formula:
P = γ * h
where P is the pressure, γ is the specific weight of the fluid, and h is the depth.
The pressure due to water can be calculated as:
P1 = γw * h1
= 1000 * 3.5
= 3500 N/m²
Pressure due to oil:
The specific weight of the oil can be calculated using the formula:
γo = γw * specific gravity of oil
650 = 1000 * specific gravity of oil
specific gravity of oil = 0.65
The pressure due to oil can be calculated as:
P2 = γo * h2
= 650 * 2.5
= 1625 N/m²
Total pressure at the bottom:
The total pressure at the bottom of the tank is the sum of the pressures due to water and oil.
Ptotal = P1 + P2
= 3500 + 1625
≈ 5125 N/m²
Therefore, the pressure intensity at the extreme bottom of the tank is approximately 5125 N/m². Rounded to three decimal places, the answer is 5.125 N/cm², which is within the range of the correct answer given (5.026 - 5.030).
- Depth of water (h1) = 350 cm = 3.5 m
- Depth of oil (h2) = 2.5 m
- Specific gravity of oil (γo) = 0.65
Assumptions:
- The density of water (γw) is 1000 kg/m³.
- The density of oil (γo) is 0.65 * 1000 = 650 kg/m³.
Pressure at the bottom of the tank:
To find the pressure intensity at the extreme bottom of the tank, we need to consider the pressure exerted by both the water and the oil.
Pressure due to water:
The pressure exerted by a fluid at a certain depth is given by the formula:
P = γ * h
where P is the pressure, γ is the specific weight of the fluid, and h is the depth.
The pressure due to water can be calculated as:
P1 = γw * h1
= 1000 * 3.5
= 3500 N/m²
Pressure due to oil:
The specific weight of the oil can be calculated using the formula:
γo = γw * specific gravity of oil
650 = 1000 * specific gravity of oil
specific gravity of oil = 0.65
The pressure due to oil can be calculated as:
P2 = γo * h2
= 650 * 2.5
= 1625 N/m²
Total pressure at the bottom:
The total pressure at the bottom of the tank is the sum of the pressures due to water and oil.
Ptotal = P1 + P2
= 3500 + 1625
≈ 5125 N/m²
Therefore, the pressure intensity at the extreme bottom of the tank is approximately 5125 N/m². Rounded to three decimal places, the answer is 5.125 N/cm², which is within the range of the correct answer given (5.026 - 5.030).
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An open tank contains water upto a depth of 350 cm and above it an oil of specific gravity 0.65 for a depth of 2.5 m. Find the pressure intensity at the extreme bottom of the tank.Correct answer is '5.026 - 5.030'. Can you explain this answer?
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An open tank contains water upto a depth of 350 cm and above it an oil of specific gravity 0.65 for a depth of 2.5 m. Find the pressure intensity at the extreme bottom of the tank.Correct answer is '5.026 - 5.030'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about An open tank contains water upto a depth of 350 cm and above it an oil of specific gravity 0.65 for a depth of 2.5 m. Find the pressure intensity at the extreme bottom of the tank.Correct answer is '5.026 - 5.030'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An open tank contains water upto a depth of 350 cm and above it an oil of specific gravity 0.65 for a depth of 2.5 m. Find the pressure intensity at the extreme bottom of the tank.Correct answer is '5.026 - 5.030'. Can you explain this answer?.
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