Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > A single array A[1 .. MAXSIZE] is used to imp...
Start Learning for Free
A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.
Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” is
Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” is
- a)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)
- b)top1 + top2 = MAXSIZE
- c)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)
- d)top1 = top2 - 1
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A single array A[1 .. MAXSIZE] is used to implement two stacks. The tw...
Since the stacks are growing from opposite ends, initially top1 = 1 and top2 = MAXSIZE. Now, to make the space usage most efficient we should allow one stack to use the maximum possible space as long as other stack doesn't need it. So, either of the stack can grow as long as there is space on the array and hence the condition must be top1 = top2 - 1;
Most Upvoted Answer
A single array A[1 .. MAXSIZE] is used to implement two stacks. The tw...
Explanation:
To use the space efficiently in a single array implementation of two stacks, we need to determine when the stacks are full.
Let's consider two variables top1 and top2 that point to the topmost elements in each stack. If the stacks grow from opposite ends of the array, then the maximum size of each stack is (MAXSIZE/2).
Now, let's look at the options given:
A) top1 = MAXSIZE / 2 and top2 = MAXSIZE / 2 - 1
This condition means that both stacks have reached the middle of the array. However, the space between the two stacks is not being used, which is not efficient.
B) top1 + top2 = MAXSIZE
This condition means that the sum of the sizes of the two stacks equals MAXSIZE. However, we cannot determine which stack is full and which stack is not, which is not efficient.
C) top1 = MAXSIZE / 2 or top2 = MAXSIZE
This condition means that one of the stacks has reached the middle of the array or the end of the array. However, we cannot determine which stack is full and which stack is not, which is not efficient.
D) top1 = top2 - 1
This condition means that the top1 and top2 are adjacent to each other, and there is no space left for any more elements. This condition ensures that both stacks are full and that the space in the array is being used efficiently.
In conclusion, option D is the correct answer as it ensures that both stacks are full, and the space in the array is being used efficiently.
To use the space efficiently in a single array implementation of two stacks, we need to determine when the stacks are full.
Let's consider two variables top1 and top2 that point to the topmost elements in each stack. If the stacks grow from opposite ends of the array, then the maximum size of each stack is (MAXSIZE/2).
Now, let's look at the options given:
A) top1 = MAXSIZE / 2 and top2 = MAXSIZE / 2 - 1
This condition means that both stacks have reached the middle of the array. However, the space between the two stacks is not being used, which is not efficient.
B) top1 + top2 = MAXSIZE
This condition means that the sum of the sizes of the two stacks equals MAXSIZE. However, we cannot determine which stack is full and which stack is not, which is not efficient.
C) top1 = MAXSIZE / 2 or top2 = MAXSIZE
This condition means that one of the stacks has reached the middle of the array or the end of the array. However, we cannot determine which stack is full and which stack is not, which is not efficient.
D) top1 = top2 - 1
This condition means that the top1 and top2 are adjacent to each other, and there is no space left for any more elements. This condition ensures that both stacks are full and that the space in the array is being used efficiently.
In conclusion, option D is the correct answer as it ensures that both stacks are full, and the space in the array is being used efficiently.
Attention Computer Science Engineering (CSE) Students!
To make sure you are not studying endlessly, EduRev has designed Computer Science Engineering (CSE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Computer Science Engineering (CSE).
|
Explore Courses for Computer Science Engineering (CSE) exam
|
|
Similar Computer Science Engineering (CSE) Doubts
Top Courses for Computer Science Engineering (CSE)View all
A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” isa)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)b)top1 + top2 = MAXSIZEc)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)d)top1 = top2 - 1Correct answer is option 'D'. Can you explain this answer?
Question Description
A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” isa)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)b)top1 + top2 = MAXSIZEc)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)d)top1 = top2 - 1Correct answer is option 'D'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” isa)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)b)top1 + top2 = MAXSIZEc)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)d)top1 = top2 - 1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” isa)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)b)top1 + top2 = MAXSIZEc)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)d)top1 = top2 - 1Correct answer is option 'D'. Can you explain this answer?.
A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” isa)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)b)top1 + top2 = MAXSIZEc)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)d)top1 = top2 - 1Correct answer is option 'D'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” isa)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)b)top1 + top2 = MAXSIZEc)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)d)top1 = top2 - 1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” isa)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)b)top1 + top2 = MAXSIZEc)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)d)top1 = top2 - 1Correct answer is option 'D'. Can you explain this answer?.
Solutions for A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” isa)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)b)top1 + top2 = MAXSIZEc)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)d)top1 = top2 - 1Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
Here you can find the meaning of A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” isa)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)b)top1 + top2 = MAXSIZEc)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)d)top1 = top2 - 1Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” isa)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)b)top1 + top2 = MAXSIZEc)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)d)top1 = top2 - 1Correct answer is option 'D'. Can you explain this answer?, a detailed solution for A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” isa)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)b)top1 + top2 = MAXSIZEc)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)d)top1 = top2 - 1Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” isa)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)b)top1 + top2 = MAXSIZEc)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)d)top1 = top2 - 1Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A single array A[1 .. MAXSIZE] is used to implement two stacks. The two stacks grow from opposite ends of the array.Variables top1 and top 2 (top < top 2) point to the location of the topmost element in each of the stacks. If the space is to be used efficiently, the condition for “stack full” isa)top1 = MAXSIZE / 2) and (top2 = MAXSIZE / 2 + 1)b)top1 + top2 = MAXSIZEc)(top1 = MAXSIZE / 2) or (top2 = MAXSIZE)d)top1 = top2 - 1Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
|
|
Explore Courses for Computer Science Engineering (CSE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup