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An internally compensated op amp has a dc open-loop gain of 106 V/V and an AC open-loop gain of 40 dB at 10 kHz. Estimate its gain–bandwidth product and its expected gain at 1 kHz.
  • a)
    0.1 MHz and -60 db
  • b)
    10 MHz and -60 db
  • c)
    10 MHz and 60 db
  • d)
    1 MHz and 60 db
Correct answer is option 'D'. Can you explain this answer?
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An internally compensated op amp has a dc open-loop gain of 106 V/V an...
-bandwidth product.

The gain-bandwidth product (GBP) can be calculated using the formula:

GBP = Aol x f

Where Aol is the open-loop gain and f is the frequency at which the gain is measured.

Given that the dc open-loop gain is 106 V/V, we can assume that the gain is constant up to a certain frequency. Therefore, we can estimate the GBP by using the AC open-loop gain of 40 dB at 10 kHz:

Aol = 10^(40/20) = 100

f = 10 kHz

GBP = Aol x f = 100 x 10,000 = 1,000,000 Hz

So the estimated gain-bandwidth product of the internally compensated op amp is 1,000,000 Hz.
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An internally compensated op amp has a dc open-loop gain of 106 V/V and an AC open-loop gain of 40 dB at 10 kHz. Estimate its gain–bandwidth product and its expected gain at 1 kHz.a)0.1 MHz and -60 dbb)10 MHz and -60 dbc)10 MHz and 60 dbd)1 MHz and 60 dbCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An internally compensated op amp has a dc open-loop gain of 106 V/V and an AC open-loop gain of 40 dB at 10 kHz. Estimate its gain–bandwidth product and its expected gain at 1 kHz.a)0.1 MHz and -60 dbb)10 MHz and -60 dbc)10 MHz and 60 dbd)1 MHz and 60 dbCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An internally compensated op amp has a dc open-loop gain of 106 V/V and an AC open-loop gain of 40 dB at 10 kHz. Estimate its gain–bandwidth product and its expected gain at 1 kHz.a)0.1 MHz and -60 dbb)10 MHz and -60 dbc)10 MHz and 60 dbd)1 MHz and 60 dbCorrect answer is option 'D'. Can you explain this answer?.
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