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An RCC short column (with lateral ties) of rectangular cross-section of in 250 mm ´ 300 mm reinforced with four members of 16 mm diameter longitudinal bars. The grades of steel and concrete are Fe415 and M20, respectively. Neglect eccentricity effect. Considering limit state of collapse in compression (IS 456 : 2000), the axial load carrying capacity of the column (in kN, up to one decimal place) is _____________
Correct answer is '(918.1)'. Can you explain this answer?
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An RCC short column (with lateral ties) of rectangular cross-section o...
Since eccentricity effect is being neglected so column can be considered as concentrically loaded.
Ultimate axial load carrying capacity of column.
Pu = 0.45 f ck Ag + (0.75 fy - 0.45 f ck) Asc
= 0.45 x 20 x 250 x 300 + ( 0.75 x 415 x 20 )
= 91.1 kN
Ultimate axial load carrying capacity of column.
Pu = 0.45 f ck Ag + (0.75 fy - 0.45 f ck) Asc
= 0.45 x 20 x 250 x 300 + ( 0.75 x 415 x 20 )
= 91.1 kN
Most Upvoted Answer
An RCC short column (with lateral ties) of rectangular cross-section o...
X 400 mm has a height of 3 meters. The column is subjected to a compressive load of 500 kN. The concrete used has a compressive strength of 25 MPa and the steel reinforcement used has a yield strength of 415 MPa.
To determine the required amount of steel reinforcement, we can use the formula:
As = (0.85 * fck * Ac) / fy
Where:
As = Area of steel reinforcement
fck = Compressive strength of concrete
Ac = Cross-sectional area of concrete
fy = Yield strength of steel reinforcement
First, we need to calculate the cross-sectional area of the concrete column:
Ac = 250 mm x 400 mm = 100,000 mm^2 = 0.1 m^2
Next, we can calculate the required area of steel reinforcement:
As = (0.85 * 25 MPa * 0.1 m^2) / 415 MPa
As = (21.25 N/mm^2 * 0.1 m^2) / 415 N/mm^2
As = 0.051 m^2
Now, we can calculate the required diameter of the steel reinforcement:
As = (π * d^2) / 4
0.051 m^2 = (π * d^2) / 4
d^2 = (0.051 m^2 * 4) / π
d^2 ≈ 0.065 m^2
d ≈ 0.255 m
Therefore, the required diameter of the steel reinforcement is approximately 255 mm.
To determine the required amount of steel reinforcement, we can use the formula:
As = (0.85 * fck * Ac) / fy
Where:
As = Area of steel reinforcement
fck = Compressive strength of concrete
Ac = Cross-sectional area of concrete
fy = Yield strength of steel reinforcement
First, we need to calculate the cross-sectional area of the concrete column:
Ac = 250 mm x 400 mm = 100,000 mm^2 = 0.1 m^2
Next, we can calculate the required area of steel reinforcement:
As = (0.85 * 25 MPa * 0.1 m^2) / 415 MPa
As = (21.25 N/mm^2 * 0.1 m^2) / 415 N/mm^2
As = 0.051 m^2
Now, we can calculate the required diameter of the steel reinforcement:
As = (π * d^2) / 4
0.051 m^2 = (π * d^2) / 4
d^2 = (0.051 m^2 * 4) / π
d^2 ≈ 0.065 m^2
d ≈ 0.255 m
Therefore, the required diameter of the steel reinforcement is approximately 255 mm.
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An RCC short column (with lateral ties) of rectangular cross-section of in 250 mm ´ 300 mm reinforced with four members of 16 mm diameter longitudinal bars. The grades of steel and concrete are Fe415 and M20, respectively. Neglect eccentricity effect. Considering limit state of collapse in compression (IS 456 : 2000), the axial load carrying capacity of the column (in kN, up to one decimal place) is _____________Correct answer is '(918.1)'. Can you explain this answer?
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An RCC short column (with lateral ties) of rectangular cross-section of in 250 mm ´ 300 mm reinforced with four members of 16 mm diameter longitudinal bars. The grades of steel and concrete are Fe415 and M20, respectively. Neglect eccentricity effect. Considering limit state of collapse in compression (IS 456 : 2000), the axial load carrying capacity of the column (in kN, up to one decimal place) is _____________Correct answer is '(918.1)'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about An RCC short column (with lateral ties) of rectangular cross-section of in 250 mm ´ 300 mm reinforced with four members of 16 mm diameter longitudinal bars. The grades of steel and concrete are Fe415 and M20, respectively. Neglect eccentricity effect. Considering limit state of collapse in compression (IS 456 : 2000), the axial load carrying capacity of the column (in kN, up to one decimal place) is _____________Correct answer is '(918.1)'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An RCC short column (with lateral ties) of rectangular cross-section of in 250 mm ´ 300 mm reinforced with four members of 16 mm diameter longitudinal bars. The grades of steel and concrete are Fe415 and M20, respectively. Neglect eccentricity effect. Considering limit state of collapse in compression (IS 456 : 2000), the axial load carrying capacity of the column (in kN, up to one decimal place) is _____________Correct answer is '(918.1)'. Can you explain this answer?.
An RCC short column (with lateral ties) of rectangular cross-section of in 250 mm ´ 300 mm reinforced with four members of 16 mm diameter longitudinal bars. The grades of steel and concrete are Fe415 and M20, respectively. Neglect eccentricity effect. Considering limit state of collapse in compression (IS 456 : 2000), the axial load carrying capacity of the column (in kN, up to one decimal place) is _____________Correct answer is '(918.1)'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about An RCC short column (with lateral ties) of rectangular cross-section of in 250 mm ´ 300 mm reinforced with four members of 16 mm diameter longitudinal bars. The grades of steel and concrete are Fe415 and M20, respectively. Neglect eccentricity effect. Considering limit state of collapse in compression (IS 456 : 2000), the axial load carrying capacity of the column (in kN, up to one decimal place) is _____________Correct answer is '(918.1)'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An RCC short column (with lateral ties) of rectangular cross-section of in 250 mm ´ 300 mm reinforced with four members of 16 mm diameter longitudinal bars. The grades of steel and concrete are Fe415 and M20, respectively. Neglect eccentricity effect. Considering limit state of collapse in compression (IS 456 : 2000), the axial load carrying capacity of the column (in kN, up to one decimal place) is _____________Correct answer is '(918.1)'. Can you explain this answer?.
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