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A cantilever beam of length 2 m with a square section of side length 0.1 m is loaded vertically at the free end. The vertical displacement at the free end is 5 mm. The beam is made of steel with Young’s modulus of 2.0 x 1011 N/m2. The maximum bending stress at the fixed end of the cantilver is 
  • a)
    20.0 MPa
  • b)
    37.5 MPa
  • c)
    60.0 MPa
  • d)
    75.0 MPa
Correct answer is option 'B'. Can you explain this answer?
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A cantilever beam of length 2 m with a square section of side length 0...


Deflection 

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A cantilever beam of length 2 m with a square section of side length 0...
's modulus of 200 GPa. The moment of inertia for a square section is (1/12) * a^4, where 'a' is the side length of the square.

To find the vertical displacement at the free end of the cantilever beam, we can use the formula for deflection in a cantilever beam under a point load:

δ = (F * L^3) / (3 * E * I)

Where:
δ = vertical displacement at the free end
F = load applied at the free end
L = length of the cantilever beam
E = Young's modulus
I = moment of inertia

In this case, F = mg, where m is the mass and g is the acceleration due to gravity. Since the load is applied vertically, F = mg.

Given:
L = 2 m
a = 0.1 m
δ = 5 mm = 0.005 m
E = 200 GPa = 200 * 10^9 Pa

First, let's calculate the moment of inertia for the square section:

I = (1/12) * a^4
I = (1/12) * (0.1^4)
I = 0.0000083333 m^4

Next, we need to convert the load into force:

F = mg

To calculate the mass, we need to find the volume of the square section:

Volume = a^2 * L
Volume = 0.1^2 * 2
Volume = 0.02 m^3

The mass can be calculated using the density of steel, which is approximately 7850 kg/m^3:

m = density * volume
m = 7850 * 0.02
m = 157 kg

Now, we can calculate the force:

F = mg
F = 157 * 9.8
F = 1538.6 N

Finally, we can substitute the values into the formula for deflection:

δ = (F * L^3) / (3 * E * I)
0.005 = (1538.6 * 2^3) / (3 * 200 * 10^9 * 0.0000083333)
0.005 = 6154.4 / (0.05 * 10^9 * 0.0000083333)
0.005 = 6154.4 / (4.1667 * 10^-6)
0.005 = 1476614400

Therefore, the vertical displacement at the free end of the cantilever beam is approximately 1476614400 mm.
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A cantilever beam of length 2 m with a square section of side length 0.1 m is loaded vertically at the free end. The vertical displacement at the free end is 5 mm. The beam is made of steel with Young’s modulus of 2.0 x 1011 N/m2. The maximum bending stress at the fixed end of the cantilver isa)20.0 MPab)37.5 MPac)60.0 MPad)75.0 MPaCorrect answer is option 'B'. Can you explain this answer?
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