A cantilever beam of span 4 m and cross-sectional are 0.3 m wide and 0...
Problem Statement
A cantilever beam of span 4 m and cross-sectional area 0.3 m wide and 0.4 m deep is subjected to a concentrated load of 10 kN at the free end. Neglecting self-weight, the maximum bending stress at a section 2 m from the free end will be?
Solution
To solve this problem, we need to use the formula for maximum bending stress in a cantilever beam:
σ = Mc / I
- σ is the maximum bending stress
- M is the bending moment at the section
- c is the distance from the neutral axis to the outermost fiber
- I is the moment of inertia of the cross-sectional area
We can first calculate the bending moment at the section 2 m from the free end:
M = Wl - Wx
- W is the concentrated load
- l is the span of the beam
- x is the distance from the free end to the section
Substituting the given values, we get:
M = 10 kN * 4 m - 10 kN * 2 m = 20 kNm
Next, we need to calculate the moment of inertia of the cross-sectional area:
I = (bd^3) / 12
- b is the width of the cross-sectional area
- d is the depth of the cross-sectional area
Substituting the given values, we get:
I = (0.3 m * 0.4 m^3) / 12 = 0.004 m^4
Finally, we can calculate the maximum bending stress at the section:
σ = Mc / I
σ = (20 kNm * 0.2 m) / 0.004 m^4 = 100 MPa
Therefore, the maximum bending stress at the section 2 m from the free end is 100 MPa.