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Consider an IP packet with a length of 4,500 bytes that includes a 20-byte IPv4 header ans 40-byte TCP header. The packet is forwarded to an IPv4 router that supports a Maximum Transmission Unit (MTU) of 600 bytes. Assume that the length of the IP header in all the outgoing fragments of this packet is 20 bytes. Assume that the fragmentation offset value stored in the first fragment is 0. The fragmentation offset value stored in the third fragment is ______ . 
Note -This was Numerical Type question.
  • a)
    0
  • b)
    72
  • c)
    144
  • d)
    216
Correct answer is option 'C'. Can you explain this answer?
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Consider an IP packet with a length of 4,500 bytes that includes a 20-...
MTU = 600 bytes and IP Header = 20 bytes So, Payload will be 600 - 20 = 580 bytes 580 is not multiple of 8, but we know fragment size should be multiple of 8. So fragment size = 576 bytes Kth fragmentation offset value = Fragment Size * (Kth fragment - 1) / Scaling Factor Offset value of 3rd fragment = 576 * (3 - 1) / 8 = 144
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Consider an IP packet with a length of 4,500 bytes that includes a 20-...
To answer this question, we need to understand how IP packet fragmentation works and calculate the fragmentation offset value for the third fragment.

- IP Packet Length: 4,500 bytes
- IPv4 Header Length: 20 bytes
- TCP Header Length: 40 bytes
- Maximum Transmission Unit (MTU): 600 bytes

We can calculate the payload size by subtracting the header sizes from the total packet length:
Payload Size = Packet Length - IPv4 Header Length - TCP Header Length
Payload Size = 4,500 - 20 - 40
Payload Size = 4,440 bytes

Since the MTU is 600 bytes, each fragment should be equal to or smaller than this size. We need to calculate the number of fragments required to transmit the entire payload.

Number of Fragments = ceil(Payload Size / MTU)
Number of Fragments = ceil(4,440 / 600)
Number of Fragments = 8

Now, let's calculate the fragmentation offset for each fragment.

- Fragment 1:
Fragment Offset = 0 (first fragment)
Fragment Length = MTU - IPv4 Header Length
Fragment Length = 600 - 20
Fragment Length = 580 bytes

- Fragment 2:
Fragment Offset = Fragment Length / 8
Fragment Offset = 580 / 8
Fragment Offset = 72

- Fragment 3:
Fragment Offset = Fragment Offset of Previous Fragment + Fragment Length / 8
Fragment Offset = 72 + (600 - 20) / 8
Fragment Offset = 72 + 580 / 8
Fragment Offset = 144

Therefore, the fragmentation offset value stored in the third fragment is 144 (option C).
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Consider an IP packet with a length of 4,500 bytes that includes a 20-byte IPv4 header ans 40-byte TCP header. The packet is forwarded to an IPv4 router that supports a Maximum Transmission Unit (MTU) of 600 bytes. Assume that the length of the IP header in all the outgoing fragments of this packet is 20 bytes. Assume that the fragmentation offset value stored in the first fragment is 0. The fragmentation offset value stored in the third fragment is ______ .Note -This was Numerical Type question.a)0b)72c)144d)216Correct answer is option 'C'. Can you explain this answer?
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