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An IP datagram of size 1000 bytes arrives at a router. The router has to forward this packet on a link whose MTU (maximum transmission unit) is 100 bytes. Assume that the size of the IP header is 20 bytes. The number of fragments that the IP datagram will be divided into for transmission is :
  • a)
    10
  • b)
    50
  • c)
    12
  • d)
    13
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
An IP datagram of size 1000 bytes arrives at a router. The router has ...
MTU = 100 bytes
Size of IP header = 20 bytes
So, size of data that can be transmitted in one fragment = 100 – 20 = 80 bytes
Size of data to be transmitted = Size of datagram – size of header = 1000 – 20 = 980 bytes
Now, we have a datagram of size 1000 bytes.
So, we need ceil(980/80) = 13 fragments.
Thus, there will be 13 fragments of the datagram.
So, D is the correct choice.
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Most Upvoted Answer
An IP datagram of size 1000 bytes arrives at a router. The router has ...
Given information:
- Size of IP datagram = 1000 bytes
- MTU of link = 100 bytes
- Size of IP header = 20 bytes

To transmit an IP datagram larger than the MTU of a link, the datagram needs to be fragmented into smaller packets. Each fragment will have its own IP header and will be transmitted separately.

Formula for calculating number of fragments:
(Number of bytes in IP datagram - Size of IP header) / (MTU - Size of IP header)

Substituting the given values in the formula, we get:
(1000 - 20) / (100 - 20) = 13

Therefore, the IP datagram will be divided into 13 fragments for transmission.
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An IP datagram of size 1000 bytes arrives at a router. The router has to forward this packet on a link whose MTU (maximum transmission unit) is 100 bytes. Assume that the size of the IP header is 20 bytes. The number of fragments that the IP datagram will be divided into for transmission is :a)10b)50c)12d)13Correct answer is option 'D'. Can you explain this answer?
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