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The dispersion equation of a waveguide, which relates the wavenumber k to the frequency ω, is
where the speed of light c = 3 × 108 m/s, and ωo is a constant. If the group velocity is 2 × 108 m/s, then the phase velocity is
  • a)
    1.5 × 108 m/s
  • b)
    2 × 108 m/s
  • c)
    4.5 × 108 m/s
  • d)
    3 × 108 m/s
Correct answer is option 'C'. Can you explain this answer?
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The dispersion equation of a waveguide, which relates the wavenumber k to the frequency ω, is where the speed of light c = 3 × 108 m/s, and ωo is a constant. If the group velocity is 2 × 108 m/s, then the phase velocity isa)1.5 × 108 m/sb)2 × 108 m/sc)4.5 × 108 m/sd)3 × 108 m/sCorrect answer is option 'C'. Can you explain this answer?
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The dispersion equation of a waveguide, which relates the wavenumber k to the frequency ω, is where the speed of light c = 3 × 108 m/s, and ωo is a constant. If the group velocity is 2 × 108 m/s, then the phase velocity isa)1.5 × 108 m/sb)2 × 108 m/sc)4.5 × 108 m/sd)3 × 108 m/sCorrect answer is option 'C'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The dispersion equation of a waveguide, which relates the wavenumber k to the frequency ω, is where the speed of light c = 3 × 108 m/s, and ωo is a constant. If the group velocity is 2 × 108 m/s, then the phase velocity isa)1.5 × 108 m/sb)2 × 108 m/sc)4.5 × 108 m/sd)3 × 108 m/sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The dispersion equation of a waveguide, which relates the wavenumber k to the frequency ω, is where the speed of light c = 3 × 108 m/s, and ωo is a constant. If the group velocity is 2 × 108 m/s, then the phase velocity isa)1.5 × 108 m/sb)2 × 108 m/sc)4.5 × 108 m/sd)3 × 108 m/sCorrect answer is option 'C'. Can you explain this answer?.
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