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In a 132 kV system, the series inductance up to the point of circuit breaker location is 50 mH. The shunt capacitance at the circuit breaker terminal is 0.05 μF. The critical value of resistance in ohms required to be connected across the circuit breaker contacts which will give no transient oscillation is _____________.
Correct answer is 'R = 500Ω'. Can you explain this answer?
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Verified Answer
In a 132 kV system, the series inductance up to the point of circuit b...
Given data L = 50mH, C = 0.05 μF
Critical resistance to avoid current shopping will be given as
R = 500Ω
Critical resistance to avoid current shopping will be given as
R = 500Ω
Most Upvoted Answer
In a 132 kV system, the series inductance up to the point of circuit b...
ΜF. The length of the line is 50 km and the surge impedance is 400 Ω. Determine the surge impedance loading (SIL) and the surge impedance voltage (SIV) at the circuit breaker terminal.
SIL = surge impedance loading
SIV = surge impedance voltage
We can use the following formulas to calculate SIL and SIV:
SIL = (Vp / √2)^2 / Z0
SIV = Vp / √2
where Vp is the peak voltage of the surge and Z0 is the surge impedance of the line.
To find Vp, we can use the formula:
Vp = √2 x Vrms
where Vrms is the rated voltage of the system, which is 132 kV.
Vp = √2 x 132 kV = 186.4 kV
Now we can calculate the surge impedance:
Z0 = √(L/C) = √(50 mH / 0.05 μF) = 200 Ω
Using these values, we can calculate SIL:
SIL = (186.4 kV / √2)^2 / 200 Ω = 8.3 MW
And we can calculate SIV:
SIV = 186.4 kV / √2 = 131.8 kV
Therefore, the surge impedance loading at the circuit breaker terminal is 8.3 MW and the surge impedance voltage is 131.8 kV.
SIL = surge impedance loading
SIV = surge impedance voltage
We can use the following formulas to calculate SIL and SIV:
SIL = (Vp / √2)^2 / Z0
SIV = Vp / √2
where Vp is the peak voltage of the surge and Z0 is the surge impedance of the line.
To find Vp, we can use the formula:
Vp = √2 x Vrms
where Vrms is the rated voltage of the system, which is 132 kV.
Vp = √2 x 132 kV = 186.4 kV
Now we can calculate the surge impedance:
Z0 = √(L/C) = √(50 mH / 0.05 μF) = 200 Ω
Using these values, we can calculate SIL:
SIL = (186.4 kV / √2)^2 / 200 Ω = 8.3 MW
And we can calculate SIV:
SIV = 186.4 kV / √2 = 131.8 kV
Therefore, the surge impedance loading at the circuit breaker terminal is 8.3 MW and the surge impedance voltage is 131.8 kV.
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In a 132 kV system, the series inductance up to the point of circuit breaker location is 50 mH. The shunt capacitance at the circuit breaker terminal is 0.05 μF. The critical value of resistance in ohms required to be connected across the circuit breaker contacts which will give no transient oscillation is _____________.Correct answer is 'R = 500Ω'. Can you explain this answer?
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In a 132 kV system, the series inductance up to the point of circuit breaker location is 50 mH. The shunt capacitance at the circuit breaker terminal is 0.05 μF. The critical value of resistance in ohms required to be connected across the circuit breaker contacts which will give no transient oscillation is _____________.Correct answer is 'R = 500Ω'. Can you explain this answer?, a detailed solution for In a 132 kV system, the series inductance up to the point of circuit breaker location is 50 mH. The shunt capacitance at the circuit breaker terminal is 0.05 μF. The critical value of resistance in ohms required to be connected across the circuit breaker contacts which will give no transient oscillation is _____________.Correct answer is 'R = 500Ω'. Can you explain this answer? has been provided alongside types of In a 132 kV system, the series inductance up to the point of circuit breaker location is 50 mH. The shunt capacitance at the circuit breaker terminal is 0.05 μF. The critical value of resistance in ohms required to be connected across the circuit breaker contacts which will give no transient oscillation is _____________.Correct answer is 'R = 500Ω'. Can you explain this answer? theory, EduRev gives you an
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