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A random variable X takes -1 and +1 with probabilities 0.2 and 0.8, respectively. It is transmitted across a channel which adds noise N, so that the random variable at the channel output is Y = X + N. The noise n is independent of X, and is uniformly distributed over the interval [-2, 2]. The receiver makes a decisionWhere the threshold θ ∈ [-1, 1] is chosen so as to minimize the probability of error Pr The minimum probability of error, rounded off to 1 decimal place, is ______________.Correct answer is '0.1'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A random variable X takes -1 and +1 with probabilities 0.2 and 0.8, respectively. It is transmitted across a channel which adds noise N, so that the random variable at the channel output is Y = X + N. The noise n is independent of X, and is uniformly distributed over the interval [-2, 2]. The receiver makes a decisionWhere the threshold θ ∈ [-1, 1] is chosen so as to minimize the probability of error Pr The minimum probability of error, rounded off to 1 decimal place, is ______________.Correct answer is '0.1'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A random variable X takes -1 and +1 with probabilities 0.2 and 0.8, respectively. It is transmitted across a channel which adds noise N, so that the random variable at the channel output is Y = X + N. The noise n is independent of X, and is uniformly distributed over the interval [-2, 2]. The receiver makes a decisionWhere the threshold θ ∈ [-1, 1] is chosen so as to minimize the probability of error Pr The minimum probability of error, rounded off to 1 decimal place, is ______________.Correct answer is '0.1'. Can you explain this answer?.

Solutions for A random variable X takes -1 and +1 with probabilities 0.2 and 0.8, respectively. It is transmitted across a channel which adds noise N, so that the random variable at the channel output is Y = X + N. The noise n is independent of X, and is uniformly distributed over the interval [-2, 2]. The receiver makes a decisionWhere the threshold θ ∈ [-1, 1] is chosen so as to minimize the probability of error Pr The minimum probability of error, rounded off to 1 decimal place, is ______________.Correct answer is '0.1'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE). Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.

Here you can find the meaning of A random variable X takes -1 and +1 with probabilities 0.2 and 0.8, respectively. It is transmitted across a channel which adds noise N, so that the random variable at the channel output is Y = X + N. The noise n is independent of X, and is uniformly distributed over the interval [-2, 2]. The receiver makes a decisionWhere the threshold θ ∈ [-1, 1] is chosen so as to minimize the probability of error Pr The minimum probability of error, rounded off to 1 decimal place, is ______________.Correct answer is '0.1'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A random variable X takes -1 and +1 with probabilities 0.2 and 0.8, respectively. It is transmitted across a channel which adds noise N, so that the random variable at the channel output is Y = X + N. The noise n is independent of X, and is uniformly distributed over the interval [-2, 2]. The receiver makes a decisionWhere the threshold θ ∈ [-1, 1] is chosen so as to minimize the probability of error Pr The minimum probability of error, rounded off to 1 decimal place, is ______________.Correct answer is '0.1'. Can you explain this answer?, a detailed solution for A random variable X takes -1 and +1 with probabilities 0.2 and 0.8, respectively. It is transmitted across a channel which adds noise N, so that the random variable at the channel output is Y = X + N. The noise n is independent of X, and is uniformly distributed over the interval [-2, 2]. The receiver makes a decisionWhere the threshold θ ∈ [-1, 1] is chosen so as to minimize the probability of error Pr The minimum probability of error, rounded off to 1 decimal place, is ______________.Correct answer is '0.1'. Can you explain this answer? has been provided alongside types of A random variable X takes -1 and +1 with probabilities 0.2 and 0.8, respectively. It is transmitted across a channel which adds noise N, so that the random variable at the channel output is Y = X + N. The noise n is independent of X, and is uniformly distributed over the interval [-2, 2]. The receiver makes a decisionWhere the threshold θ ∈ [-1, 1] is chosen so as to minimize the probability of error Pr The minimum probability of error, rounded off to 1 decimal place, is ______________.Correct answer is '0.1'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A random variable X takes -1 and +1 with probabilities 0.2 and 0.8, respectively. It is transmitted across a channel which adds noise N, so that the random variable at the channel output is Y = X + N. The noise n is independent of X, and is uniformly distributed over the interval [-2, 2]. The receiver makes a decisionWhere the threshold θ ∈ [-1, 1] is chosen so as to minimize the probability of error Pr The minimum probability of error, rounded off to 1 decimal place, is ______________.Correct answer is '0.1'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.