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A single-phase fully-controlled thyristor converter is used to obtain an average voltage of 180 V with 10 A constant current to feed a DC load. It is fed from single-phase AC supply of 230 V, 50 Hz. Neglect the source impedance. The power factor (round off to two decimal places) of AC mains is ___________.
Correct answer is '0.78'. Can you explain this answer?
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A single-phase fully-controlled thyristor converter is used to obtain ...
Vsr Isr cos φ = VoIo
For single phase fully – controlled converter
Io = Isr = 10A
For single phase fully – controlled converter
Io = Isr = 10A
Most Upvoted Answer
A single-phase fully-controlled thyristor converter is used to obtain ...
Given:
- Average voltage output of the thyristor converter = 180 V
- Constant current to the DC load = 10 A
- AC supply voltage = 230 V, 50 Hz
To find:
- Power factor of the AC mains
Solution:
Step 1: Calculate the output power of the thyristor converter
The output power of the thyristor converter can be calculated using the average voltage and current values.
Output Power (Pout) = Average Voltage (Vout) x Constant Current (Iout)
Pout = 180 V x 10 A = 1800 W
Step 2: Calculate the input power of the thyristor converter
Since the converter is fully-controlled, the input power is equal to the output power.
Pin = Pout = 1800 W
Step 3: Calculate the apparent power of the AC mains
The apparent power (S) can be calculated using the formula:
S = Vrms x Irms
Where Vrms is the root mean square voltage and Irms is the root mean square current.
For a single-phase AC supply,
Vrms = Vm/sqrt(2) and Irms = Im/sqrt(2)
Where Vm is the maximum voltage and Im is the maximum current.
Vm = 230 V and Im = Pin/Vm
Im = 1800 W / 230 V = 7.83 A
Therefore,
Vrms = 230/sqrt(2) = 162.64 V
Irms = 7.83/sqrt(2) = 5.53 A
S = 162.64 V x 5.53 A = 899.85 VA
Step 4: Calculate the power factor (PF)
The power factor (PF) can be calculated using the formula:
PF = Pout / S
PF = 1800 W / 899.85 VA = 0.78 (rounded off to two decimal places)
Conclusion:
The power factor of the AC mains is 0.78.
- Average voltage output of the thyristor converter = 180 V
- Constant current to the DC load = 10 A
- AC supply voltage = 230 V, 50 Hz
To find:
- Power factor of the AC mains
Solution:
Step 1: Calculate the output power of the thyristor converter
The output power of the thyristor converter can be calculated using the average voltage and current values.
Output Power (Pout) = Average Voltage (Vout) x Constant Current (Iout)
Pout = 180 V x 10 A = 1800 W
Step 2: Calculate the input power of the thyristor converter
Since the converter is fully-controlled, the input power is equal to the output power.
Pin = Pout = 1800 W
Step 3: Calculate the apparent power of the AC mains
The apparent power (S) can be calculated using the formula:
S = Vrms x Irms
Where Vrms is the root mean square voltage and Irms is the root mean square current.
For a single-phase AC supply,
Vrms = Vm/sqrt(2) and Irms = Im/sqrt(2)
Where Vm is the maximum voltage and Im is the maximum current.
Vm = 230 V and Im = Pin/Vm
Im = 1800 W / 230 V = 7.83 A
Therefore,
Vrms = 230/sqrt(2) = 162.64 V
Irms = 7.83/sqrt(2) = 5.53 A
S = 162.64 V x 5.53 A = 899.85 VA
Step 4: Calculate the power factor (PF)
The power factor (PF) can be calculated using the formula:
PF = Pout / S
PF = 1800 W / 899.85 VA = 0.78 (rounded off to two decimal places)
Conclusion:
The power factor of the AC mains is 0.78.
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A single-phase fully-controlled thyristor converter is used to obtain an average voltage of 180 V with 10 A constant current to feed a DC load. It is fed from single-phase AC supply of 230 V, 50 Hz. Neglect the source impedance. The power factor (round off to two decimal places) of AC mains is ___________.Correct answer is '0.78'. Can you explain this answer?
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A single-phase fully-controlled thyristor converter is used to obtain an average voltage of 180 V with 10 A constant current to feed a DC load. It is fed from single-phase AC supply of 230 V, 50 Hz. Neglect the source impedance. The power factor (round off to two decimal places) of AC mains is ___________.Correct answer is '0.78'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A single-phase fully-controlled thyristor converter is used to obtain an average voltage of 180 V with 10 A constant current to feed a DC load. It is fed from single-phase AC supply of 230 V, 50 Hz. Neglect the source impedance. The power factor (round off to two decimal places) of AC mains is ___________.Correct answer is '0.78'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single-phase fully-controlled thyristor converter is used to obtain an average voltage of 180 V with 10 A constant current to feed a DC load. It is fed from single-phase AC supply of 230 V, 50 Hz. Neglect the source impedance. The power factor (round off to two decimal places) of AC mains is ___________.Correct answer is '0.78'. Can you explain this answer?.
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